我正在开发一个搜索网站，用户可以在该网站上搜索他们最喜欢的城市餐厅。我的数据库已设置，我的搜索页面已设置。我还能够返回搜索结果。但是，我在分页逻辑方面遇到问题，无法获得结果。我怀疑 MySQL 查询需要调整，但我不知道这些变化是什么。
这是我的 Search.php 代码:
<title>Results</title> <link href='./style.css' type='text/css' />
<style>b,p {
font-family: 'Segoe UI Web Light', 'Segoe UI Light', 'Segoe UI Web Regular', 'Segoe UI', 'Segoe UI Symbol', 'Helvetica Neue',
Arial; color:#000; font-size:18px;
}
body { font-family: 'Segoe UI Light', 'Segoe UI Light', 'Segoe UI Web
Regular', 'Segoe UI', 'Segoe UI Symbol', 'Helvetica Neue', Arial;
color:#000; font-size:22px;
} a { text-decoration:none; color:#47a3da} a:hover {
text-decoration:underline; color:black }
* { margin:0px; padding:0px }
ol.timeline { list-style:none}ol.timeline li{
position:relative;border-bottom:2px #dedede dashed; padding:12px;
}ol.timeline li:first-child{} .morebox { font-weight:light;
color:#333333; text-align:center; border:solid 1px #333333;
padding:9px; margin-top:9px; margin-bottom:9px;
-moz-border-radius: 7px;-webkit-border-radius: 7px; } .morebox a{
color:#333333; text-decoration:none} .morebox a:hover{ color:#00688B;
text-decoration:none}
#container{margin-left:55px; width:780px } </style>
<?php
$start = 0; $per_page = 4;
if(!isset($_POST['query'])) {
$page = 1;
}
else {
$page = $_POST['query'];
}
if($page<=1) {
$start = 0;
}
else {
$start = $page * $per_page - $per_page;
}
####### databse connection ######## $con = mysql_connect("localhost", "database", "password");
mysql_select_db("database", $con) or die("no"); $sql = "SELECT
hotelname,address,comments,preview,cuisname FROM database.Hotel INNER
JOIN HotelCuisine ON Hotel.id = HotelCuisine.hotel_id INNER JOIN
Cuisine ON Cuisine.id = HotelCuisine.cuisine_id WHERE keywords LIKE
'%$page%'";
$num_rows = mysql_num_rows(mysql_query($sql)); $num_pages =
ceil($num_rows / $per_page); $sql .= " LIMIT $start, $per_page";
?>
<body>
<?php
//####### Fetch Results From Table ########
$result = mysql_query($sql); while($row = mysql_fetch_array($result))
{ $hotelname = $result['hotelname']; $address = $result['address'];
$comments = $result['comments']; $preview = $result['preview'];
?>
<?php
####### echo the result from table ########
echo "<br>Name: <b>$hotelname</b><br>"; echo "Location:
$address<br>"; echo "$comments<br>"; echo "<a
href=$url>$preview</a><br>";
}
?>
</body>
<?php
####### Math OF +1 and -1 for the page ########
$prev = $page - 1; $next = $page + 1;
echo"<hr>"; echo "<a href='?page=$prev'>prev</a> "; echo " <a
href='?page=$next'>next</a> ";
?>
最佳答案
首先，您确定您粘贴到此处的代码是您回显 $sql 时的代码吗？根据我的理解，查询应该是
SELECT hotelname,address,comments,preview,cuisname FROM database.Hotel INNER JOIN HotelCuisine ON Hotel.id = HotelCuisine.hotel_id INNER JOIN Cuisine ON Cuisine.id = HotelCuisine.cuisine_id WHERE keywords LIKE '%biryani%' LIMIT 0, 4
这里 0 是结果的起始索引，4 是返回的行数。
此外，当您检索行数时，您的代码效率不高。这个可以优化。
如果我要实现它，我会使用以下逻辑:
<?php
$start = 0;
$per_page = 4;
if(!isset($_POST['page'])) {
$page = 1;
} else {
$page = intval($_POST['page']);
}
####### databse connection ########
$con = mysql_connect("localhost", "database", "password");
mysql_select_db("database", $con) or die("no");
$sql = "SELECT COUNT(1) AS num_of_rows FROM database.Hotel INNER
JOIN HotelCuisine ON Hotel.id = HotelCuisine.hotel_id INNER JOIN
Cuisine ON Cuisine.id = HotelCuisine.cuisine_id WHERE keywords LIKE
'%$_POST['query']%'";
$num_rows = mysql_fetch_array(mysql_query($sql))["num_of_rows"];
$num_pages = ceil($num_rows / $per_page);
$sql = "SELECT hotelname,address,comments,preview,cuisname FROM database.Hotel INNER
JOIN HotelCuisine ON Hotel.id = HotelCuisine.hotel_id INNER JOIN
Cuisine ON Cuisine.id = HotelCuisine.cuisine_id WHERE keywords LIKE
'%$_POST['query']%' LIMIT ".($page-1)*$per_page.",".$per_page;
$result = mysql_query($sql);
?>
<body>
<?php
//####### Fetch Results From Table ########
while($row = mysql_fetch_array($result)){
$hotelname = $result['hotelname'];
$address = $result['address'];
$comments = $result['comments'];
$preview = $result['preview'];
####### echo the result from table ########
echo "<br>Name: <b>$hotelname</b><br>";
echo "Location: $address<br>";
echo "$comments<br>";
echo "<a href=$url>$preview</a><br>";
}
####### Math OF +1 and -1 for the page ########
$prev = $page - 1;
$next = $page + 1;
echo"<hr>";
echo "<a href='?page=$prev'>prev</a> ";
echo " <a href='?page=$next'>next</a> ";
?>
</body>
我再次建议您先在命令行或phpMyAdmin中运行$sql来检查查询是否正确。
关于php - PHP 中的搜索结果分页逻辑，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/24308056/