我想验证用户名是否在我的数据库中，但它不起作用。我在数据库中添加用户名，但是当我验证其显示用户名可用时，现在该怎么办。我把我的代码
这就是 Dbconnector.php
<?php
class DbConnector {
var $theQuery;
var $link;
function DbConnector(){
// Get the main settings from the array we just loaded
$host = 'host';
$db = 'cms';
$user = 'root';
$pass = '';
// Connect to the database
$this->link = mysql_connect($host, $user, $pass);
mysql_select_db($db);
register_shutdown_function(array(&$this, 'close'));
}
//*** Function: query, Purpose: Execute a database query ***
function query($query) {
$this->theQuery = $query;
return mysql_query($query, $this->link);
}
//*** Function: fetchArray, Purpose: Get array of query results ***
function fetchArray($result) {
return mysql_fetch_array($result);
}
//*** Function: close, Purpose: Close the connection ***
function close() {
mysql_close($this->link);
}
}
?>
这就是 Check.php
<?php
include("dbConnector.php");
$connector = new DbConnector();
$username = trim(strtolower($_POST['username']));
$username = mysql_escape_string($username);
$query = "SELECT Username FROM admin WHERE Username = '$username' LIMIT 1";
$result = $connector->query($query);
$num = mysql_num_rows($result);
echo $num;
mysql_close();
?>
这就是我的index.php
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Papermashup.com | jQuery PHP Username Checker</title>
<link href="../style.css" rel="stylesheet" type="text/css" />
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.js"></script>
<script>
$(document).ready(function(){
$('#username').keyup(username_check);
});
function username_check(){
var username = $('#username').val();
if(username == "" || username.length < 4){
$('#username').css('border', '3px #CCC solid');
$('#tick').hide();
}else{
jQuery.ajax({
type: "POST",
url: "check.php",
data: 'username='+ username,
cache: false,
success: function(response){
if(response == 1){
$('#username').css('border', '3px #C33 solid');
$('#tick').hide();
$('#cross').fadeIn();
}else{
$('#username').css('border', '3px #090 solid');
$('#cross').hide();
$('#tick').fadeIn();
}
}
});
}
}
</script>
<style>
#username{
padding:3px;
font-size:18px;
border:3px #CCC solid;
}
#tick{display:none}
#cross{display:none}
</style>
</head>
<body>
Here are some usernames that have been put in the database:<br/><br />
Hammad, Huzaifa , Hanzlah<br/><br/>
Username: <input name="username" id="username" type="text" />
<img id="tick" src="tick.png" width="16" height="16"/>
<img id="cross" src="cross.png" width="16" height="16"/>
</body>
</html>
最佳答案
我认为问题出在你的 HTML 和 Js 上。
首先添加一个表单并给它一个id，例如#load然后输入 <input...../>形式。
现在更改您的 Jquery.ajax({ url:至url +'check.php?'+$("#load").serialize() .
尝试一下，一定要使用Js Console来检查ajax请求是否发送及其反馈。
关于php - 用户名验证不起作用，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/24425760/