MySql 选择不工作

Question

我有两张 table 。

一张饭 table

id   type

1    lunch
2    lunch
3    dinner

两个user_history表

ID Meal_id  User_id  create  

1   2         4       1404638939  

现在我想从第一表中选择所有餐食，但有条件

如果表二的meal_id与餐食表id匹配并且创建日期与当前日期相同，则跳过表一中的该行

我使用此代码但无法正常工作

SELECT m.* FROM `meal` AS m LEFT JOIN user_history
                 ON user_history.meal_id != m.id and date(FROM_UNIXTIME(user_history.create))!=CURRENT_DATE() where m.meal_type = 'Lunch'

Answer 1

SELECT m.* FROM `meal` AS m 
LEFT JOIN user_history
ON user_history.Meal_id != m.id and date(FROM_UNIXTIME(user_history.create))=CURRENT_DATE() 
where m.type LIKE "%lunch%"