我有一个 mysql 表，它附加了一个触发器，可以将该表中的更改记录到第二个表中
CREATE TRIGGER log_table BEFORE UPDATE ON table1
FOR EACH ROW BEGIN
INSERT INTO log_table(filed) VALUES(NEW.field);
END;
//
现在，如果我从 PHP 执行 INSERT INTO table1，然后调用 mysqli_insert_id()。
这会返回 table1 中的新 ID 吗？或者log_table中的新ID？
最佳答案
在 INSERT 语句之后调用的
LAST_INSERT_ID() 将返回 table1(INSERT 语句)中的新 ID，而不是 log_table(触发器)中的 ID。
这记录在 LAST_INSERT_ID 的手册部分中:
Within the body of a stored routine (procedure or function) or a trigger, the value of LAST_INSERT_ID() changes the same way as for statements executed outside the body of these kinds of objects. The effect of a stored routine or trigger upon the value of LAST_INSERT_ID() that is seen by following statements depends on the kind of routine:
If a stored procedure executes statements that change the value of LAST_INSERT_ID(), the changed value is seen by statements that follow the procedure call.
For stored functions and triggers that change the value, the value is restored when the function or trigger ends, so following statements will not see a changed value.
关于php - BEFORE UPDATE 触发器会影响 mysqli_insert_id 结果吗？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/25896229/