我已经写了
SELECT DISTINCT r.id_destination
, lo.location1
, lo.location2
, lo.destination
, lo.zip
, ld.id_field
, da.identification entity
, da.data
FROM pl_records r
JOIN pl_records_detail rd
ON r.id_order = rd.id_order
LEFT JOIN pl_attribue at
ON rd.product_attribute_id = at.id_product_attribute
LEFT JOIN pl_profile pr
ON at.id_attribute = pr.id_attribute
JOIN pl_location lo
ON r.id_address_delivery = lo.id_address
JOIN pl_situation si
ON r.current_state = si.id_order_state
LEFT JOIN pl_location_detail
ON r.id_cart = ld.id_cart
LEFT JOIN pl_data da
ON ld.id_field = da.id_field
WHERE r.id_record = 6
它返回的输出会因为“entity”和“data”字段包含许多值而重复!
id_destination location1 location2 destination zip id_field entity data
55 east coast street ON CN 454 28 89 Please process it with safe standards
55 east coast street ON CN 454 28 90 Payment will be COD
55 east coast street ON CN 454 28 78 updates not necessary
55 east coast street ON CN 454 28 92 no withdrawal of details
55 east coast street ON CN 454 28 99 added records
如何防止值重复？或者是否可以如何对最后两个字段的不同值进行分组
最佳答案
也许您正在寻找group_concat()？
SELECT r.id_destination, lo.location1, lo.location2, lo.destination, lo.zip,
GROUP_CONCAT(DISTINCT ld.id_field) as id_fields,
GROUP_CONCAT(DISTINCT da.identification) AS entities
da.data
FROM pl_records r JOIN
pl_records_detail rd
ON r.id_order = rd.id_order LEFT JOIN
pl_attribue at
ON rd.product_attribute_id = at.id_product_attribute LEFT JOIN
pl_profile p
ON at.id_attribute = pr.id_attribute JOIN
pl_location lo
ON r.id_address_delivery = lo.id_address JOIN
pl_situation si
ON r.current_state = si.id_order_state LEFT JOIN
pl_location_detail
ON r.id_cart = ld.id_cart LEFT JOIN
pl_data da
on ld.id_field = da.id_field
WHERE r.id_record = 6
GROUP BY r.id_destination, lo.location1, lo.location2, lo.destination, lo.zip
关于mysql - 如何对同一字段的不同值进行分组，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/27239094/