java - 如何修复 hibernate hbm.xml 文件以使复合主键正常工作? (映射异常)

标签 java mysql sql hibernate orm

演示问题的 GitHub 示例

https://github.com/jl431/Example.git

重现错误所需的所有代码都在这里。

还需要启动 mysql 服务器并更改 hibernate 文件中的连接详细信息。

错误

Initial SessionFactory creation failed.org.hibernate.MappingException: Could not determine type for: beans.User, at table: RATINGS, for columns: [org.hibernate.mapping.Column(USER_ID)]
Exception in thread "main" java.lang.ExceptionInInitializerError
    at simple.HibernateUtil.buildSessionFactory(HibernateUtil.java:26)
    at simple.HibernateUtil.<clinit>(HibernateUtil.java:10)
    at simple.MovieManager.<init>(MovieManager.java:9)
    at simple.MovieManager.main(MovieManager.java:13)
Caused by: org.hibernate.MappingException: Could not determine type for: beans.User, at table: RATINGS, for columns: [org.hibernate.mapping.Column(USER_ID)]
    at org.hibernate.mapping.SimpleValue.getType(SimpleValue.java:336)
    at org.hibernate.tuple.PropertyFactory.buildStandardProperty(PropertyFactory.java:353)
    at org.hibernate.tuple.component.ComponentMetamodel.<init>(ComponentMetamodel.java:71)
    at org.hibernate.mapping.Component.getType(Component.java:180)
    at org.hibernate.mapping.SimpleValue.isValid(SimpleValue.java:310)
    at org.hibernate.mapping.RootClass.validate(RootClass.java:271)
    at org.hibernate.cfg.Configuration.validate(Configuration.java:1360)
    at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1851)
    at simple.HibernateUtil.buildSessionFactory(HibernateUtil.java:19)
    ... 3 more

以下是我认为问题所在的几个关键文件。其余代码可从上面的 github 存储库 URL 获取。

hibernate.cfg.xml

<?xml version='1.0' encoding='utf-8'?>
<!DOCTYPE hibernate-configuration PUBLIC
        "-//Hibernate/Hibernate Configuration DTD 3.0//EN"
        "http://www.hibernate.org/dtd/hibernate-configuration-3.0.dtd">

<hibernate-configuration>
    <session-factory>

        <!-- Database connection settings -->
        <property name="connection.driver_class">com.mysql.jdbc.Driver</property>
        <property name="connection.url">jdbc:mysql://localhost:3306/testingbeta</property>
        <property name="connection.username">root</property>
        <property name="connection.password"></property>


        <!-- JDBC connection pool (use the built-in) -->
        <property name="connection.pool_size">1</property>

        <!-- SQL dialect -->
        <property name="dialect">org.hibernate.dialect.MySQLDialect</property>

        <!-- Enable Hibernate's automatic session context management -->
        <property name="current_session_context_class">thread</property>

        <!-- Disable the second-level cache  -->
        <property name="cache.provider_class">org.hibernate.cache.internal.NoCacheProvider</property>

        <!-- Echo all executed SQL to stdout -->
        <property name="show_sql">true</property>

        <!-- Drop and re-create the database schema on startup -->
        <property name="hbm2ddl.auto">create</property>

        <mapping resource="Movie.hbm.xml"/>
        <mapping resource="User.hbm.xml"/>
        <mapping resource="Rating.hbm.xml"/>

    </session-factory>
</hibernate-configuration>

Rating.hbm.xml

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
        "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
        "http://www.hibernate.org/dtd/hibernate-mapping-3.0.dtd">

<hibernate-mapping package="beans">
    <class name="Rating" table="RATINGS">
        <composite-id name="RatingId" class="RatingId">
            <key-property name="user" column="USER_ID" />
            <key-property name="movie" column="MOVIE_ID" />
        </composite-id>

        <property name="rating" />
    </class>
</hibernate-mapping>

评级.java

package beans;

import java.util.Date;

public class Rating {
    private RatingId ratingId;
    private int rating;
    private Date timestamp;

    public Rating() {}  // No arg contructor for hibernate

    public Rating(RatingId ratingId, int rating) {
        super();
        this.ratingId = ratingId;
        this.rating = rating;
    }

    public RatingId getRatingId() {
        return ratingId;
    }

    public void setRatingId(RatingId ratingId) {
        this.ratingId = ratingId;
    }

    public int getRating() {
        return rating;
    }

    public void setRating(int rating) {
        this.rating = rating;
    }
}

RatingId.java

package beans;

import java.io.Serializable;

public class RatingId implements Serializable {
    private User user;
    private Movie movie;

    public RatingId(User user, Movie movie) {
        this.user = user;
        this.movie = movie;
    }

    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
    }

    public Movie getMovie() {
        return movie;
    }

    public void setMovie(Movie movie) {
        this.movie = movie;
    }

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((movie == null) ? 0 : movie.hashCode());
        result = prime * result + ((user == null) ? 0 : user.hashCode());
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        RatingId other = (RatingId) obj;
        if (movie == null) {
            if (other.movie != null)
                return false;
        } else if (!movie.equals(other.movie))
            return false;
        if (user == null) {
            if (other.user != null)
                return false;
        } else if (!user.equals(other.user))
            return false;
        return true;
    }
}

最佳答案

我怀疑复合键列是否可以位于不同的表中(在我们的例子中 - USERS 和 MOVIE 表)。据我了解,它们需要出现在评级表中。 我尝试将它们映射到同一个表中,并且能够成功地保留评级对象。我正在使用 JPA 注释。通过注释,配置更加简单。下面是代码。

注意 - 复合键是在 JPA 中使用 @Embeddeble@EmbeddedId 注释定义的。

@Embeddable
public class User {

    @Column(name = "USER_ID")
    private long userId;
    @Column(name = "EMAIL_ADDRESS")
    private String email;
    public User() {}

    public User(long userId, String email, String password) {
        this.userId = userId;
        this.email = email;
    }
    public long getUserId() {
        return userId;
    }
    public void setUserId(long userId) {
        this.userId = userId;
    }
    public String getEmail() {
        return email;
    }
    public void setEmail(String email) {
        this.email = email;
    }
}

@Embeddable
public class Movie {
    @Column(name = "MOVIE_ID")
    private long movieId;

    @Column(name = "MOVIE_NAME")
    private String title;

    public Movie() {}
    public Movie(long movieId, String title) {
        this.movieId = movieId;
        this.title = title;
    }
    public long getMovieId() {
        return movieId;
    }
    public void setMovieId(long movieId) {
        this.movieId = movieId;
    }
    public String getTitle() {
        return title;
    }
    public void setTitle(String title) {
        this.title = title;
    }
}

@Embeddable
public class RatingId implements Serializable {

    @Embedded
    private User user;  //Embeddable inside Embeddable.
    @Embedded
    private Movie movie;

    public RatingId() {
    }

    public RatingId(User user, Movie movie) {
        this.user = user;
        this.movie = movie;
    }

    public User getUser() {
        return user;
    }

    public void setUser(User user) {
        this.user = user;
    }

    public Movie getMovie() {
        return movie;
    }

    public void setMovie(Movie movie) {
        this.movie = movie;
    }

    @Override
    public int hashCode() {
        final int prime = 31;
        int result = 1;
        result = prime * result + ((movie == null) ? 0 : movie.hashCode());
        result = prime * result + ((user == null) ? 0 : user.hashCode());
        return result;
    }

    @Override
    public boolean equals(Object obj) {
        if (this == obj)
            return true;
        if (obj == null)
            return false;
        if (getClass() != obj.getClass())
            return false;
        RatingId other = (RatingId) obj;
        if (movie == null) {
            if (other.movie != null)
                return false;
        } else if (!movie.equals(other.movie))
            return false;
        if (user == null) {
            if (other.user != null)
                return false;
        } else if (!user.equals(other.user))
            return false;
        return true;
    }
}

@Entity
@Table(name = "RATING")
public class Rating {

    @EmbeddedId
    private RatingId ratingId;
    private int rating;
    private Date timestamp;

    public Rating() {}  // No arg contructor for hibernate

    public Rating(RatingId ratingId, int rating) {
        super();
        this.ratingId = ratingId;
        this.rating = rating;
    }

    public RatingId getRatingId() {
        return ratingId;
    }

    public void setRatingId(RatingId ratingId) {
        this.ratingId = ratingId;
    }

    public int getRating() {
        return rating;
    }

    public void setRating(int rating) {
        this.rating = rating;
    }
}

调用entityManager.persist( rating)将评级对象保存在数据库中。总而言之,数据库中只有一个表 - RATINGS,它具有所有必需的属性 - 用户、电影和评级。 这也是你所想象的吗?

关于java - 如何修复 hibernate hbm.xml 文件以使复合主键正常工作? (映射异常),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27643483/

相关文章:

sql - 将 ResultSet 传递给 Postgresql 函数

mysql - SQL 选择第一个可能的重复项,还包括按日期排序的单项

Java SimpleDateFormat 解析返回错误的日期

c# - 更新 Entity Framework 时出现错误

java - 加载 100MB 文件时出现 OutOfMemoryError,尽管有 550MB 堆

Mysql - 从分组数据中获取n个结果

c# - 对 MySql 列进行计时 C# 和 php

php - 根据MySQL中的相关表选择数据

Java:动态变量响应为 JSON

java - 类中的this关键字