您好,我正在使用 spring mvc 3 和 hibernate 4 开发一个 Web 应用程序。我对所有配置都使用注释。
当我尝试选择一个实体时,出现错误:
DaoException: unexpected token: MEMBER near line 1, column 37 [from clanwar.model.ClanMember where MEMBER = :member]
at clanwar.dao.impl.ClanMemberDao.findByPlayerId(ClanMemberDao.java:71)
如果我使用 .createSQLQuery()
进行查询,hibernate 会返回一个 ClanMember
实体的 Object[]
实例。
DAO 中的方法:
@Repository
@Transactional
...
@Override
public ClanMember findByPlayerId(int id) throws DaoException {
ClanMember foundMember;
try {
foundMember = (ClanMember) getSession()
.createQuery("from ClanMember where MEMBER = :member")
.setParameter("member", id)
.uniqueResult();
} catch (Exception e) {
throw new DaoException(e.getMessage());
}
return foundMember;
}
...
实体:
@Entity
@Table(name = "CLAN_MEMBERS")
public class ClanMember implements Serializable {
private static final long serialVersionUID = 1L;
@Id
@ManyToOne
@JoinColumn(name = "CLAN")
private Clan clan;
@Id
@ManyToOne
@JoinColumn(name = "MEMBER")
private Player member;
@ManyToOne
@JoinColumn(name = "ROLE")
private ClanRole role;
public ClanMember() {}
// Setters and getters
}
表 CLAN_MEMBERS:
+--------+---------+------+-----+---------+-------+
| Field | Type | Null | Key | Default | Extra |
+--------+---------+------+-----+---------+-------+
| CLAN | int(11) | NO | PRI | NULL | |
| MEMBER | int(11) | NO | PRI | NULL | |
| ROLE | int(11) | NO | | 1 | |
+--------+---------+------+-----+---------+-------+
我做错了什么? 提前致谢。
最佳答案
member
是 HQL 中的保留字。通过添加表别名来转义它。
此外,由于 member
的类型为 Player
,因此当您的 where 子句
包含 member
时,您需要提供Player
类型的参数。或者,如果您想像现在一样提供 ID,则需要显式搜索 id
:
所以要么:
foundMember = (ClanMember) getSession()
.createQuery("from ClanMember c where c.member = :member")
.setParameter("member", someInstanceOfPlayer);
.uniqueResult();
或
foundMember = (ClanMember) getSession()
.createQuery("from ClanMember c where c.member = :member")
.setParameter("member", idOfAPlayer);
.uniqueResult();
关于java - 在 Hibernate 4 中获取错误意外 token ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/27688366/