php - 返回元值等于的帖子数

Question

我使用高级自定义字段插件创建了一个自定义字段。该字段称为“状态”，默认情况下等于“即将到来”，然后它将更改为正确或错误。

然后，我尝试查询状态元值等于正确或错误的所有帖子。然而，即使我在下面的查询中设置了它，它仍然返回所有帖子的计数。我已经仔细检查并计算了有多少帖子等于正确或错误，但我仍然得到错误的计数。我做错了什么？

SELECT count(DISTINCT posts.ID) as count, AVG(odds.meta_value) as ave
  FROM $wpdb->posts posts
  LEFT JOIN $wpdb->postmeta stat
             ON posts.ID = stat.post_id
            AND stat.meta_key = 'status'
  LEFT JOIN $wpdb->postmeta odds
             ON posts.ID = odds.post_id
            AND odds.meta_key = 'odds'
  LEFT JOIN $wpdb->term_relationships tr ON posts.ID = tr.object_id
  LEFT JOIN $wpdb->term_taxonomy t ON tr.term_taxonomy_id = t.term_taxonomy_id 
  WHERE stat.meta_value    = 'wrong'
   OR stat.meta_value    = 'correct'
   AND posts.post_status      = 'publish'
   AND t.taxonomy = 'category'
   AND t.term_id  = 4
   OR t.term_id  = 5
   OR t.term_id  = 6

Answer 1

您应该使用括号将应该放在一起的内容组合在一起:

SELECT count(DISTINCT posts.ID) as count, AVG(odds.meta_value) as ave
FROM $wpdb->posts posts
LEFT JOIN $wpdb->postmeta stat
    ON posts.ID = stat.post_id
    AND stat.meta_key = 'status'
LEFT JOIN $wpdb->postmeta odds
    ON posts.ID = odds.post_id
    AND odds.meta_key = 'odds'
LEFT JOIN $wpdb->term_relationships tr
    ON posts.ID = tr.object_id
LEFT JOIN $wpdb->term_taxonomy t
    ON tr.term_taxonomy_id = t.term_taxonomy_id 
WHERE (stat.meta_value    = 'wrong'
   OR stat.meta_value    = 'correct')
   AND posts.post_status      = 'publish'
   AND t.taxonomy = 'category'
   AND (t.term_id  = 4
   OR t.term_id  = 5
   OR t.term_id  = 6)