MYSQL 查询帮助 JOIN 表

Question

我在查询时遇到了一些问题，希望有人可以指导我解决这个问题？我想这应该是可以实现的。我有两张 table 。表 A 存储小时数，表 B 存储驾驶时间。我正在努力让所有每天工作超过 6 小时的人都能够做到这一点。但我还需要获取特定日期的驾驶时间，他们一天的驾驶时间超过 6 小时。我希望我说得有道理。这是我现在正在使用的查询，正在努力让每天工作超过 6 小时的每个人也能获得分钟数。行驶时间存储在名为 ies_mileage 的表 B 中，字段为持续时间。我尝试了几件事但没有成功。

SELECT 
    wk_date,
    full_name, 
    SUM(hours) AS HOURS 
FROM `ies_weekly` 
    LEFT JOIN infant_specialist 
        ON ies_weekly.is_id = infant_specialist.is_id 
WHERE wk_date BETWEEN '2015-01-16' AND '2015-01-31' 
GROUP BY 
    DAY(wk_date), 
    ies_weekly.is_id 
HAVING SUM(hours) > 6 
ORDER BY full_name  ASC

这是有效的，当我尝试添加持续时间时，总数变得困惑并且不再准确。这是我尝试过的

SELECT 
    wk_date,
    full_name, 
    SUM(hours) AS HOURS, 
    SUM(duration) AS minutes 
FROM 
    `ies_weekly` 
    LEFT JOIN infant_specialist 
        ON ies_weekly.is_id = infant_specialist.is_id 
    LEFT JOIN ies_mileage 
        ON ies_weekly.wk_date = ies_mileage.mil_date 
        AND ies_weekly.is_id = ies_mileage.ies_id 
WHERE wk_date BETWEEN '2015-01-16' AND '2015-01-31' 
GROUP BY 
    DAY(wk_date), 
    ies_weekly.is_id 
HAVING SUM(hours) > 6
ORDER BY full_name  ASC

Answer 1

SELECT full_name, wk_date, SUM(hours) HOURS,
    (Select Sum(duration)
     From ies_mileage
     Where mil_date = w.wk_date
         and ies_id = w.is_id) DrivingTime
FROM ies_weekly w
    LEFT JOIN infant_specialist i
     ON i.is_id = w.is_id 
WHERE wk_date BETWEEN '2015-01-16' AND '2015-01-31' 
GROUP BY DAY(wk_date), w.is_id 
HAVING SUM(hours) > 6 
ORDER BY full_name ASC