php - MySQL 匹配搜索中的比较运算符

Question

下面是 SQL 语句，我很难放置一个 where 语句来获取匹配生成的分数，并且只返回分数超过 6 的产品。

SELECT product_id, image, title, part_num, price, discount_id, vat, 
       MATCH (title,part_num,description) 
       AGAINST ('SEARCH HERE') AS score 
FROM main_products AS p 
WHERE status = 1 
     AND MATCH(title,part_num,description) AGAINST ('SEARCH HERE') 
ORDER BY score desc, title ASC

我已经尝试过了，但是这不起作用。它会导致此错误:Documentation #1054 - 'where Clause' 中的未知列 'score'

SELECT product_id, image, title, part_num, price, discount_id, vat, 
      MATCH (title,part_num,description) 
      AGAINST ('SEARCH HERE') AS score 
FROM main_products AS p WHERE status = 1 AND score > 6 
     AND MATCH(title,part_num,description) AGAINST ('SEARCH HERE') 
ORDER BY score desc, title ASC

Answer 1

这个怎么样？

SELECT product_id, image, title, part_num, price, discount_id, vat, 
      MATCH (title,part_num,description) 
      AGAINST ('SEARCH HERE') AS score 
FROM main_products 
WHERE status = 1 
      AND MATCH(title,part_num,description) AGAINST ('SEARCH HERE')
HAVING score > 6 
ORDER BY score desc, title ASC