我是 SQL 查询新手,正在尝试将多行压缩为具有相似标识符的单行。下面是一个例子:
Table orders:
groupid | question | answer
|-----------------------------------|
abc000 | First Name | John
abc000 | Last Name | Doe
abc000 | City | Denver
... | ... | ...
abc000 | Entry | Individual
abc000 | Shirt Size | X-Large
abc001 | First Name | Jane
abc001 | Last Name | Doe
abc001 | City | Seattle
... | ... | ...
abc001 | Entry | Individual
(No Shirt entry)
我试图让它看起来像:
表格确认(所需输出):
组ID |姓氏 |名字 |城市 | ... |衬衫尺码
|-------------------------------------------------------- ------------|
abc000 |美国能源部 |约翰 |丹佛 | ... |超大号
abc001 |美国能源部 |简|西雅图 | ... |小
表格确认(实际输出):
组ID |姓氏 |名字 |城市 | ... |衬衫尺码
|-------------------------------------------------------- ------------|
abc000 |美国能源部 |约翰 |丹佛 | ... |
abc000 |美国能源部 |约翰 |丹佛 | ... |超大号
abc001 |美国能源部 |简|西雅图 | ... |
查询是:
SELECT DISTINCT om.groupid, om.fid, om.eid, f.subtitle,
IF(oi.question = 'First Name', oi.answer, '') AS fname,
IF(oi1.question = 'Last Name', oi1.answer, '') AS lname,
IF(oi2.question = 'City', oi2.answer, '') AS city,
IF(oi3.question = 'State', oi3.answer, '') AS state,
IF(oi4.question = 'Birthdate', oi4.answer, '') AS bday,
IF(oi5.question = 'Gender', oi5.answer, '') AS gender,
IF ( (oi6.question LIKE '%fee'), oi6.answer, '') as event,
IF ( (oi7.question = 'shirt size (unisex cotton)'), oi7.answer, '') as shirt
FROM ordermeta om
JOIN orders o ON o.orderid=om.orderid
LEFT JOIN orderitems oi ON oi.groupid=om.groupid
LEFT JOIN orderitems oi1 ON oi1.groupid=om.groupid
LEFT JOIN orderitems oi2 ON oi2.groupid=om.groupid
LEFT JOIN orderitems oi3 ON oi3.groupid=om.groupid
LEFT JOIN orderitems oi4 ON oi4.groupid=om.groupid
LEFT JOIN orderitems oi5 ON oi5.groupid=om.groupid
LEFT JOIN orderitems oi6 ON oi6.groupid=om.groupid
LEFT JOIN orderitems oi7 ON oi7.groupid=om.groupid
WHERE oi.question = 'First NAME'
AND oi1.question = 'Last Name'
AND oi2.question = 'City'
AND oi3.question = 'State'
AND oi4.question = 'Birthdate'
AND oi5.question = 'Gender'
AND oi6.question LIKE '%fee%'
ORDER BY lname ASC
如果我删除衬衫尺码,效果会很好。我添加了:
AND oi7.question = "Shirt Size"
除了它可能并不总是“衬衫尺码”,而是更像“%衬衫尺码%”,并且当没有=衬衫尺码的问题时,我希望它留下空或空白。使用 AND,它只会给我也有衬衫问题的结果。 (140 个结果中的 55 个)
当前代码,当问题=“衬衫尺寸”存在时,我得到两个条目(一个是空白的,另一个有良好的信息)。所有其他条目都有一个条目,没有任何信息。 (140 个结果中的 195 个)
我尝试了多种不同的方法,例如 CASE、IF THEN 语句。他们都做同样的事情,效果很好,直到我添加衬衫问题。
如果您需要更多信息,请告诉我。谢谢。
我尝试过的 SE 类型之一的示例: Combine multiple rows into one row MySQL
最佳答案
我发现有两个问题有“衬衫”。这是创建适合模型的第二个条目,以将第二行留为空白,因为它不适合选择中的第二个过滤器。这是我最终不得不写的内容。
SELECT DISTINCT om.groupid, om.fid, om.eid, f.subtitle,
IF(oi.question = 'First Name', oi.answer, '') AS fname,
IF(oi1.question = 'Last Name', oi1.answer, '') AS lname,
IF(oi2.question = 'City', oi2.answer, '') AS city,
IF(oi3.question = 'State', oi3.answer, '') AS state,
IF(oi4.question = 'Birthdate', oi4.answer, '') AS bday,
IF(oi5.question = 'Gender', oi5.answer, '') AS gender,
IF ( (oi6.question LIKE '%fee'), oi6.answer, '') as event,
IF ( (oi7.question IN ('Youth Shirts','Event Shirt','Tech Shirt Size','Series Shirt','Choose Event Shirt(s)','Shirt Size (Included in Entry)','Regular T-Shirt OR Tech Shirt - Select Size/Type','shirt size (unisex cotton)')), oi7.answer, '') as shirt
FROM ordermeta om
JOIN orders o ON o.orderid=om.orderid
LEFT JOIN orderitems oi ON oi.groupid=om.groupid AND oi.question = 'First Name'
LEFT JOIN orderitems oi1 ON oi1.groupid=om.groupid AND oi1.question = 'Last Name'
LEFT JOIN orderitems oi2 ON oi2.groupid=om.groupid AND oi2.question = 'City'
LEFT JOIN orderitems oi3 ON oi3.groupid=om.groupid AND oi3.question = 'State'
LEFT JOIN orderitems oi4 ON oi4.groupid=om.groupid AND oi4.question = 'Birthdate'
LEFT JOIN orderitems oi5 ON oi5.groupid=om.groupid AND oi5.question = 'Gender'
LEFT JOIN orderitems oi6 ON oi6.groupid=om.groupid AND oi6.question LIKE '%fee%'
LEFT JOIN orderitems oi7 ON oi7.groupid=om.groupid AND oi7.question IN ('Youth Shirts','Event Shirt','Tech Shirt Size','Series Shirt','Choose Event Shirt(s)','Shirt Size (Included in Entry)','Regular T-Shirt OR Tech Shirt - Select Size/Type','shirt size (unisex cotton)')
LEFT JOIN forms f ON f.fid=om.fid
WHERE om.status = 1
AND o.paid = 1
AND f.fid=$fid
ORDER BY lname ASC
这是一个非常难看的地方,因为衬衫尺码条目是灵活的...需要标准化该条目以使查询仅查找 LIKE“衬衫尺码%”
关于mysql - 从同一个表到具有相似标识符的单行的多行,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29225020/