php - 将 php 输出重新插入数据库

Question

这里提供的代码不是用于生产而是用于开发，我有一个 php 页面如下:

mysql_select_db($database_dd, $dbs);
$query_Getuser = sprintf("SELECT * FROM users, firstname, lastname WHERE status = 'active'",
$Getuser = mysql_query($query_Getuser, $dd) or die(mysql_error());
$row_Getuser = mysql_fetch_assoc($Getuser);
$totalRows_Getuser = mysql_num_rows($Getuser);

if($Getuser){
    // insert my my output values into my new table
}

<table class="table table-responsive">
  <tr>
    <td>User</td>
    <td><?php echo $row_Getuser['username']; ?></td>
  </tr>
  <tr>
    <td>Status</td>
    <td><?php echo $row_Getuser['status']; ?></td>
  </tr>
  <tr>
    <td>Total Active Users</td>
    <td><?php echo $totalRows_Getuser ?></td>
  </tr>
  <tr>
    <td>Total Inactive Users </td>
    <td><?php echo $totalRows_WScore ?></td>
  </tr>
  </table>

问题:我厌倦了捕获输出并将其重新插入到我在数据库中创建的新表中。 我尝试了隐藏字段，但这需要一个页面一个按钮 isset() 然后我教授了如何使用 Session_start() 数据，例如:

$_SESSION['username'] = $_POST['username'];
$_SESSION['status'] = $_POST['status'];
$_SESSION['totalRows_Getuser'] = $_POST['totalRows_Getuser'];

我似乎无法插入数据。可以做什么？

Answer 1

你可以用 while 来做到这一点

while($row = mysql_fetch_assoc($Getuser)){

   .... <?= $row_Getuser['username'] ?>
        <?= $row_Getuser['status'] ?>

}

我更愿意让 MySQL 算数。

SELECT COUNT(users) AS ActiveUsers,* FROM users, firstname, lastname WHERE status = 'active'