php - 将数据插入数据库返回为 <br/> <font size ='1' ><table class='xdebug-error

Question

嗨，每当我执行将表单提交到数据库时，我都会遇到问题。它确实将数据提交到表单，但这是一个错误，而不是插入的数据。 index.php

<div id="postForm">
    <!-- Username of the user posting the Language Learning Object -->
    <div id="postUserName" data-role="field-contain">
        <label for="Username of user">Username of user </label>
        <input type="text" name="post_username" value="<?php echo $_SESSION['post_username']; ?>" readonly="readonly" id="post_username"/>
    </div>

    <!-- Word of the language learning object -->
    <div id="postWord" data-role="field-contain">
        <label for="Word for Language Learning Object">Word for Language Learning Object </label>
        <input type="text" name="post_word" id="post_word" />
    </div>

    <!-- Description of the word -->
    <div id="postDescription" data-role="field-contain">
        <label for="Word description">Word description </label>
        <textarea name="word_description" id="word_description"></textarea>
    </div>

    <!-- Categorization of the given word -->
    <div id="postCategorization" data-role="field-contain">
        <label for="Categorization of Word">Categorization of Word </label>
        <select name="word_categorization" id="word_categorization">
            <option value=""> Select </option>
            <option value="Adverb"> Adverb </option>
            <option value="Adjective"> Adjective </option>
            <option value="Noun"> Noun </option>
            <option value="Verb"> Verb </option>
        </select>
    </div>

    <!-- Origin of the given word -->
    <div id="postOrigin" data-role="field-contain">
        <label for="Origin of Word">Origin of Word </label>
        <input type="text" name="word_origin" id="word_origin" />
    </div>

    <!-- Getting the user's location -->
    <div id="userLocation" data-role="field-contain">
        <label for="user location">User location</label>
        <input type="text" name="user_loc" value="<?php echo $geo->city;?>" />
    </div>

    <!-- Submit Button -->
    <div id="submitPost" data-role="field-contain">
        <button name="submit_post" type="submit" id="submit_post">Create post</button>
    </div>
</div> <!-- end of Form -->

post.php

<?php

include_once( 'connect.php' );

class ManagePost {

    protected $link;

    /* Connection to database */
    function __construct(){
        $db_connect = new ManageDatabase;
        $this->link = $db_connect->databaseconnect();
        return $this->link;
    }

    /* creating language learning objects/posts */
    function addPost($username,$word,$description,$categorization,$origin,$user_loc,$date,$time) {
        $query = $this->link->prepare("INSERT INTO post (username, word, description, categorization, origin, user_loc, date, time) VALUES (?,?,?,?,?,?,?,?)");
            $values = array($username,$word,$description,$categorization,$origin,$user_loc,$date,$time);

        $query->execute($values);
        $rowCount = $query->rowCount();

        return $rowCount;
    }
}

dbpost.php

<?php

    session_start();
    include('../class/post.php');
    $post_init = new ManagePost;

    if($_POST)
    {
        $username           = $_POST['post_username'];
        $word               = $_POST['post_word'];
        $description        = $_POST['word_description'];
        $categorization     = $_POST['word_categorization'];
        $origin             = $_POST['word_origin'];
        $user_loc           = $_POST['user_loc'];
        $date               = date("Y-M-D");
        $time               = date ("H:i:s");

        $submit_post = $post_init->addPost($username, $word, $description, $categorization, $origin, $user_loc, $date, $time);

        if($submit_post == 1)
        {
            echo 'true';
        }
        else
        {
            echo 'failed to submit';
        }
    }
?>

createpost.js

$('form').submit(function() {

    if(validateWord() && validateDescription() && validateCategorization() &&  validateOrigin())
    {
        $.post('lib/dbpost.php', $('form').serialize(), function(response) {
            if(response == 'true')
            {
                showSuccess('Post submitted');
            }
            else
            {
                showError(response);
            }
        })
    }
});

当我检查 phpMyAdmin 中的表帖子时，它只是显示为这样的错误

<br /><font size='1'><table class='xdebug-error xe 

在属性中

"word, description, origin, and user_loc"

Answer 1

您可以尝试更改 add_post 函数，如下所示:

function addPost($username, $word, $description, $categorization, $origin, $user_loc, $date,$time){
    $query = $this->link->prepare("INSERT INTO post (username,word,description,categorization,origin,user_loc,date,time)
    VALUES (:username,:word,:description,:categorization,:origin,:user_loc,:date,:time)");
    $query->bindParam(':username', $username);
    $query->bindParam(':word', $word);
    $query->bindParam(':description', $description);
    $query->bindParam(':categorization', $categorization);
    $query->bindParam(':origin', $origin);
    $query->bindParam(':user_loc', $user_loc);
    $query->bindParam(':date', $date);
    $query->bindParam(':time', $time);
    $query->execute();
    $rowCount = $stmt->rowCount();
    return $rowCount;
}