PHP PDO - 显示特定的行和列

Question

我需要显示数据库的一些特定行和列

// my query
$products = $conn->prepare("SELECT * FROM products");
$products->execute();
$row_products = $products->fetch(PDO::FETCH_ASSOC);
$totalRows_products=$products->rowCount();

这展示了第一个产品

echo $row_products->name;
echo $row_products->value;`

但我需要显示一些特定的行
我不能使用 DO 或 WHILE，因为它不能是连续的
像这样的东西，但它不起作用:

My 3rd product is: <?php echo $row_products[2]->name; ?>
and my 6th product is: <?php echo $row_products[5]->name; ?>

Answer 1

您可以通过将 $products->fetch 替换为 $products->fetchAll 来获取所有记录:

<?php
$products = $conn->prepare("SELECT * FROM products");
$products->execute();
$row_products = $products->fetchAll(PDO::FETCH_ASSOC);
$totalRows_products = count($row_products):

// $row_products contains all the rows. You can even loop :
for ($i = 0; $i < $totalRows_products; ++$i)
{
    echo 'Row n° '.($i + 1).' : ';
    echo $row_products[$i]->name.' '.$row_products[$i]->value;
}