mysql - 如何在带有 SUM 的多重连接查询中包含 DISTINCT

标签 mysql join sum distinct

以下查询为我提供了几乎正确的计数,但它包含具有重复 p.promo_code 和 Submitid 值的行。如何让此查询使用 DISTINCT p.promo_code、submitid?

我尝试了一些在 SO 上看到的用于单连接查询的解决方案,例如 --- 总和 * COUNT(DISTINCT p.promo_code, Submitid)/count(*)

没有运气。 这是完整的查询:

SELECT
          SUM(CASE WHEN ISNULL(p.promo_code) 
                  AND h.account_number = c2.account_number THEN 1 ELSE 0 END) as  'no_match_acct_match',
          SUM(CASE WHEN ISNULL(p.promo_code) 
                  AND (h.account_number <> c2.account_number OR ISNULL(c2.account_number)) THEN 1 ELSE 0 END) as  'no_match',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name = CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date > @today THEN 1 ELSE 0 END) as 'future_name',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name = CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` = 'REDEEMED' THEN 1 ELSE 0 END) as 'redeemed_name',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name = CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` <> 'REDEEMED' 
                  AND p.end_date < @today
                  AND p.end_date + 259200 >= @today THEN 1 ELSE 0 END) as 'buffered_name',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name = CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` <> 'REDEEMED' 
                  AND p.end_date < @today
                  AND p.end_date + 259200 < @today THEN 1 ELSE 0 END) as 'expired_name',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name = CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` <> 'REDEEMED' 
                  AND p.end_date >= @today THEN 1 ELSE 0 END) as 'current_name',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name <> CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date > @today 
                  AND (r.resolve_status = 0 OR ISNULL(r.resolve_status)) THEN 1 ELSE 0 END) as 'future_noname',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name <> CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` = 'REDEEMED' THEN 1 ELSE 0 END) as 'redeemed_noname',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name <> CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` <> 'REDEEMED' 
                  AND p.end_date < @today
                  AND p.end_date + 259200 >= @today THEN 1 ELSE 0 END) as 'buffered_noname',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name <> CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` <> 'REDEEMED' 
                  AND p.end_date < @today
                  AND p.end_date + 259200 < @today THEN 1 ELSE 0 END) as 'expired_noname',
          SUM(CASE WHEN p.promo_code IS NOT NULL 
                  AND c.full_name <> CONCAT(h.firstname,' ',h.lastname) 
                  AND p.start_date <= @today 
                  AND p.`status` <> 'REDEEMED' 
                  AND p.end_date >= @today THEN 1 ELSE 0 END) as 'current_noname'
              FROM helpdesk h
              FORCE INDEX (help_status)
              LEFT JOIN promo_codes p
                  ON h.promo_code = p.promo_code
              LEFT JOIN customer_promocode cp
                  ON p.promo_code = cp.promo_code
              LEFT JOIN customers c
                  ON cp.customer_number = c.customer_number
              LEFT JOIN customers c2
                  ON h.account_number = c2.account_number
              LEFT OUTER JOIN redeem_queue r
                  ON p.promo_code = r.promo_code
              WHERE
                  h.help_status = 0
                  AND h.in_view_by = ''
                  AND (p.start_date  >= UNIX_TIMESTAMP(SUBDATE(CURDATE(), INTERVAL 1 YEAR))
                  OR p.start_date IS NULL) 
                  AND (ISNULL(p.promo_code) OR ISNULL(r.promo_code))

它运行得很快,解释计划看起来不错,但由于重复的数据,目前有 2 个计数被关闭。

任何和所有的帮助将不胜感激。

最佳答案

您应该对这些列使用分组依据。

SELECT
  SUM(
    CASE WHEN ISNULL(p.promo_code)
    AND h.account_number = c2.account_number THEN 1 ELSE 0 END
  ) as 'no_match_acct_match',
  SUM(
    CASE WHEN ISNULL(p.promo_code)
    AND (
      h.account_number <> c2.account_number
      OR ISNULL(c2.account_number)
    ) THEN 1 ELSE 0 END
  ) as 'no_match',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name = CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date > @today THEN 1 ELSE 0 END
  ) as 'future_name',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name = CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` = 'REDEEMED' THEN 1 ELSE 0 END
  ) as 'redeemed_name',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name = CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` <> 'REDEEMED'
    AND p.end_date < @today
    AND p.end_date + 259200 >= @today THEN 1 ELSE 0 END
  ) as 'buffered_name',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name = CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` <> 'REDEEMED'
    AND p.end_date < @today
    AND p.end_date + 259200 < @today THEN 1 ELSE 0 END
  ) as 'expired_name',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name = CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` <> 'REDEEMED'
    AND p.end_date >= @today THEN 1 ELSE 0 END
  ) as 'current_name',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name <> CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date > @today
    AND (
      r.resolve_status = 0
      OR ISNULL(r.resolve_status)
    ) THEN 1 ELSE 0 END
  ) as 'future_noname',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name <> CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` = 'REDEEMED' THEN 1 ELSE 0 END
  ) as 'redeemed_noname',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name <> CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` <> 'REDEEMED'
    AND p.end_date < @today
    AND p.end_date + 259200 >= @today THEN 1 ELSE 0 END
  ) as 'buffered_noname',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name <> CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` <> 'REDEEMED'
    AND p.end_date < @today
    AND p.end_date + 259200 < @today THEN 1 ELSE 0 END
  ) as 'expired_noname',
  SUM(
    CASE WHEN p.promo_code IS NOT NULL
    AND c.full_name <> CONCAT(h.firstname, ' ', h.lastname)
    AND p.start_date <= @today
    AND p.`status` <> 'REDEEMED'
    AND p.end_date >= @today THEN 1 ELSE 0 END
  ) as 'current_noname'
FROM
  helpdesk h FORCE INDEX (help_status)
  LEFT JOIN promo_codes p ON h.promo_code = p.promo_code
  LEFT JOIN customer_promocode cp ON p.promo_code = cp.promo_code
  LEFT JOIN customers c ON cp.customer_number = c.customer_number
  LEFT JOIN customers c2 ON h.account_number = c2.account_number
  LEFT OUTER JOIN redeem_queue r ON p.promo_code = r.promo_code
WHERE
  h.help_status = 0
  AND h.in_view_by = ''
  AND (
    p.start_date >= UNIX_TIMESTAMP(SUBDATE(CURDATE(), INTERVAL 1 YEAR))
    OR p.start_date IS NULL
  )
  AND (
    ISNULL(p.promo_code)
    OR ISNULL(r.promo_code)
  )
group by
  p.promo_code,
  submitid

关于mysql - 如何在带有 SUM 的多重连接查询中包含 DISTINCT,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30109670/

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