php - mysql 查询是否无法正常工作

Question

在我的查询中我想添加另一个条件

if((select ShowMan from preferences where `UserId`='92') == true )
 then users.gender !='female'

这是我的完整查询

SELECT *
FROM `users`
WHERE users.id != '92' AND

        users.id NOT IN (SELECT matched_user_id
                               FROM `user_matchs`
                               WHERE user_id = '92'
                              )
and
        users.id NOT IN (SELECT user_id
                               FROM `user_matchs`
                               WHERE matched_user_id = '92'
                         AND status = 'friend'
                              ) 

and if((select ShowMan from preferences where `UserId`='92') == true ) 
then users.gender !='female'

我的逻辑是ifuser 92 ShowMan值为true然后添加一个条件users.gender !='female' 如果 ShowMan 值为 false，则添加条件 users.gender !='male'

Answer 1

更改此工作的最后一部分是否有效:

and ((NOT (select ShowMan from preferences where `UserId`='92')) OR (users.gender !='female'))

或完整查询

SELECT 'users'.*
FROM `users`
JOIN preferences ON `UserID` = users.id
WHERE users.id != '92' AND
  users.id NOT IN (SELECT matched_user_id
                   FROM `user_matchs`
                   WHERE user_id = users.id
                  )
AND   users.id NOT IN (SELECT user_id
                   FROM `user_matchs`
                   WHERE matched_user_id = users.id
                   AND status = 'friend'
                  ) 
AND ((NOT `preferences`.`ShowMan`) OR (users.gender !='female'))