php - 如何使用我的php变量UserNameID删除数据库中用户的行

Question

我希望用户能够从数据库中删除他们的帐户，这将通过单击我的 php 论坛中的按钮来完成，请参阅下面的代码。

  <div  class="btn-group">
    <button style="width:200px" type="button" class="btn btn-primary">Change details</button>
    <button style="width:200px" type="button" class="btn btn-primary">Add details</button>
    <button onclick="myFunction()" style="width:200px" type="button" class="btn btn-primary">Delete details</button>
    </div>

我已经设置了数据库连接

<?php
$connection = mysql_connect('localhost', 'root', 'Oliver'); 
mysql_select_db('users');    
$query = "SELECT * FROM username WHERE username='$login_session'"; 
$result = mysql_query($query);       
while($row = mysql_fetch_array($result)){      
$name = $row['name'];
$username = $row['username'];
$sex = $row['sex'];
$phone = $row['phone'];
$email = $row['email'];
$dob = $row['dob'];
$image = $row['imagelink'];
$hobby = $row['hobby'];
$bio = $row['Bio'];
$Level = $row['Level'];
$UserNameID = $row['UserNameID'];
}    
mysql_close(); 
?>

数据库行将由来自数据库的 php 变量 UserNameID 标识

$UserNameID = $row['UserNameID'];

如果您需要更多信息，请回复我，我对编码很陌生，因此需要合作:D 非常感谢

更新 不要不喜欢，请告诉我我做错了什么，我们将不胜感激

更新

这是 session 代码

<?php
// Establishing Connection with Server by passing server_name, user_id and password as a parameter
$connection = mysql_connect("localhost", "root", "Oliver");
// Selecting Database
$db = mysql_select_db("users", $connection);
session_start();// Starting Session
// Storing Session
$user_check=$_SESSION['login_user'];
// SQL Query To Fetch Complete Information Of User
$ses_sql=mysql_query("select username from username where username='$user_check'", $connection);
$row = mysql_fetch_assoc($ses_sql);
$login_session =$row['username'];
if(!isset($login_session)){
mysql_close($connection); // Closing Connection
header('Location: home.php'); // Redirecting To Home Page
}
?>

如果数据库中的详细信息匹配，这只会让用户登录，并启动 session 来解锁其他页面

Answer 1

我认为这会让您更接近目标。

<div class="btn-group">
    <button style="width:200px" type="button" class="btn btn-primary">Change details</button>
    <button style="width:200px" type="button" class="btn btn-primary">Add details</button
    <form action="" method="post">
        <button type="submit" style="width:200px" class="btn btn-primary">Delete details</button>
        <input type="hidden" name="UserName id="UserName" value="<?php echo $login_session;?>" />
    </form>
</div>

<?php
$connection = mysql_connect('localhost', 'root', 'Oliver'); 
mysql_select_db('users');    
$query = "SELECT * FROM username WHERE username='$login_session'";
$result = mysql_query($query); 
//By the way you don't need loop here      
    while($row = mysql_fetch_array($result)){      
        $name = $row['name'];
        $username = $row['username'];
        $sex = $row['sex'];
        $phone = $row['phone'];
        $email = $row['email'];
        $dob = $row['dob'];
        $image = $row['imagelink'];
        $hobby = $row['hobby'];
        $bio = $row['Bio'];
        $Level = $row['Level'];
        $UserNameID = $row['UserNameID'];
    }
    //Here you delete record from database
        if(isset($_POST['UserName'])){
        $user = mysql_real_escape_string($_POST['UserName']);
        //Strongly suggest that use UserId to delete record not username
        $sql = "DELETE FROM username WHERE username='$user' LIMIT 1";
    }       
mysql_close(); 
?>

根据OP请求进行编辑

<?php
$connection = mysql_connect('localhost', 'root', 'Oliver'); 
mysql_select_db('users');
if(isset($_POST['UserName'])){ 
$user = mysql_real_escape_string($_POST['UserName']);
$query = "SELECT * FROM username WHERE username='$user'";
$result = mysql_query($query);
$total = mysql_num_rows($result);   
$row = mysql_fetch_array($result);
// You dont need to fetch all records just `$UserNameID` enough
$name = $row['name'];
$username = $row['username'];
$sex = $row['sex'];
$phone = $row['phone'];
$email = $row['email'];
$dob = $row['dob'];
$image = $row['imagelink'];
$hobby = $row['hobby'];
$bio = $row['Bio'];
$Level = $row['Level'];
$UserNameID = $row['UserNameID'];

//Here you delete record from database
    if($total>0){
        $sql = "DELETE FROM username WHERE UserNameID='$UserNameID' LIMIT 1";
    }
}
mysql_close(); 
?>