php - 返回MySQL中相同id组的最后一个插入行

Question

我正在使用创建付款收据，我将支付一些金额，如下例所示

此收据已创建，但仍需支付 due_amount

cust_id   cust_name  invoice_id  paid_amount  due amount  makeapayment

1001       SAS              545      76           305          sasi 

这是我查询的结果。
我必须支付到期金额 100，然后在支付相同的“id”后创建另一行查看新行旧行不查看仅留在数据库中查看像这样的结果

cust_id   cust_name  invoice_id  paid_amount  due amount  makeapayment

1001       SAS              545       76           205          sasi   

目前我正在使用查询

SELECT pid, cust_id, cust_name, date, invoice_id, invoice_date, invoice_amount, paid_amount, paymentmade, makeapayment, due_amount, status FROM print_reciept
group by cust_id having due_amount!='0' ORDER BY pid DESC          

Answer 1

我想你可以试试这个

SELECT pid, cust_id, cust_name, date, invoice_id, invoice_date, invoice_amount, paid_amount, paymentmade, makeapayment, due_amount, status 
FROM print_reciept AS pr
INNER JOIN (
    SELECT MAX(pid) AS last_pid, cust_id
    FROM print_reciept
    GROUP BY cust_id
) AS tmp ON (tmp.cust_id = pr.cust_id AND tmp.last_pid > pr.pid)
GROUP BY cust_id 
ORDER BY pid DESC