mysql - HQL/MySQL 用于列出不同项和重复项

Question

我有 20.000 多个对象的列表。这些对象有一个名为 title 的表的 fk。如果两个tipp链接到相同的标题，并且它们属于同一个包(tipp_pkg_fk，这是一个参数)，则它们被认为是重复的。 我需要所有对象的列表，并将重复项列在一起。例如:

tippA.title.name = "One"
tippB.title.name = "Two"
tippC.title.name = "Two"

理想情况下，从上面我会得到这样的列表结果:[[tippA],[tippB,tippC]]

我不知道如何做到这一点，我已经尝试过(首先在Mysql中，这样我可以测试它，然后将其更改为HQL):

select tipp.tipp_id, 1 as sortOrder
    from (select distinct a.tipp_id as id
            from title_instance_package_platform a, title_instance_package_platform b 
            where a.tipp_pkg_fk= 1 and b.tipp_pkg_fk = 1 and a.tipp_ti_fk = b.tipp_ti_fk) duplicates,
    title_instance_package_platform tipp
where tipp.tipp_id != duplicates.id
union all
select duplicates.id, 2 as sortOrder
    from (select distinct a.tipp_id as id
            from title_instance_package_platform a , title_instance_package_platform b 
            where a.tipp_pkg_fk = 1 and b.tipp_pkg_fk=1 and a.tipp_ti_fk = b.tipp_ti_fk) duplicates
order by sortOrder, id;

这个执行了 330 秒，然后我在 MySQL Workbench 中收到消息fetching，此时计算机开始死机。所以我的想法是，首先我选择所有不重复的 ID，然后选择所有重复的 ID，然后将它们合并并排序，以便它们出现在一起。我正在寻找最有效的方法来执行此操作，因为我将在通宵工作期间多次执行此查询。

对于我的 TIPP 模型，以下是映射的一部分:

static mapping = {
     pkg column:'tipp_pkg_fk', index: 'tipp_idx'
     title column:'tipp_ti_fk', index: 'tipp_idx'
}


+-----------------------------+--------------+------+-----+---------+----------------+
| Field                       | Type         | Null | Key | Default | Extra          |
+-----------------------------+--------------+------+-----+---------+----------------+
| tipp_id                     | bigint(20)   | NO   | PRI | NULL    | auto_increment |
| tipp_version                | bigint(20)   | NO   |     | NULL    |                |
| tipp_pkg_fk                 | bigint(20)   | NO   | MUL | NULL    |                |
| tipp_plat_fk                | bigint(20)   | NO   | MUL | NULL    |                |
| tipp_ti_fk                  | bigint(20)   | NO   | MUL | NULL    |                |
| date_created                | datetime     | NO   |     | NULL    |                |
| last_updated                | datetime     | NO   |     | NULL    |                |



+-----------------+---------------+------+-----+---------+----------------+
| Field           | Type          | Null | Key | Default | Extra          |
+-----------------+---------------+------+-----+---------+----------------+
| ti_id           | bigint(20)    | NO   | PRI | NULL    | auto_increment |
| ti_version      | bigint(20)    | NO   |     | NULL    |                |
| date_created    | datetime      | NO   |     | NULL    |                |
| ti_imp_id       | varchar(255)  | NO   | MUL | NULL    |                |
| last_updated    | datetime      | NO   |     | NULL    |                |
| ti_title        | varchar(1024) | YES  |     | NULL    |                |
| ti_key_title    | varchar(1024) | YES  |     | NULL    |                |
| ti_norm_title   | varchar(1024) | YES  |     | NULL    |                |
| sort_title      | varchar(1024) | YES  |     | NULL    |                |
+-----------------+---------------+------+-----+---------+----------------+

更新

经过一些更改后，它正在工作:

select tipp.tipp_id as id, 1 as sortOrder
from
    title_instance_package_platform tipp
where tipp.tipp_id not in (select distinct a.tipp_id as id
            from title_instance_package_platform a, title_instance_package_platform b 
            where a.tipp_pkg_fk= 1 and b.tipp_pkg_fk = 1 and a.tipp_ti_fk = b.tipp_ti_fk)
union all
select duplicates.id as id, 2 as sortOrder
    from (select distinct a.tipp_id as id
            from title_instance_package_platform a , title_instance_package_platform b 
            where a.tipp_pkg_fk = 1 and b.tipp_pkg_fk=1 and a.tipp_ti_fk = b.tipp_ti_fk) duplicates
order by sortOrder, id;

尽管如此，我仍然没有将重复项分组在一起，而是所有内容都以列表的形式出现，这意味着我仍然需要将它们分组。

Answer 1

你能从另一边做选择吗？ 选择所有标题和包并列出所有提示，仅当存在提示时(计数> 0)并将它们捆绑在一起以获得您显示的数组？