我有下表:
委员会[ID、名称、Total_Amount、Total_Members、Starting_Date、Ending_Date]
committee_group [ID、名称、Total_Members]
Group_Member [Id、Group_Id、Member_Name、贡献]
我想从committee_group中选择Name,其中Group_Member的贡献总和等于委员会的Total_Amount
这就是我目前所拥有的
SELECT committee_group.*, Sum(Case When group_member.Group_Id='1'
THEN group_member.Contribution
ELSE 0 END)
FROM committee_group
LEFT JOIN group_member ON group_member.Id = committee_group.Id
LEFT join comitees ON group_member.Contribution = comitees.Total_Amount
最佳答案
这应该有效,
SELECT a.id,a.Name,a.Total_Members,c.Total_Amount
FROM committee_Group a
INNER JOIN (SELECT Name,sum(Contribution) as 'Sum_Con'
FROM Group_Member
GROUP BY Name)b on a.Id=b.Id
INNER JOIN comitees c on c.Total_Amount=b.Sum_Con
and b.Name=c.Name
关于mysql - 多表连接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32370285/