php - 在帮助文件 Codeigniter 3 中查询数据库

标签 php mysql codeigniter codeigniter-3

我试图向辅助文件添加一个函数以从数据库收集额外信息。这会出现错误,因为我试图用来调用该函数的文档 ID 是以数组的形式输出的,而不是我想要的......

我的模型如下所示:

public function get_categoryads()
{

    $this->db->select('ads.id AS id, ads.userid AS userid, ads.adnr AS adnr,
  ads.location AS town, search_town.townFileName AS townlink, search_prov.provLabel AS province, 
  search_prov.subLink AS provlink,text, ad_image.image AS image,addate, r_option, R_rand,
  adcat.name AS catname,  adcat.clinkname AS clinkname, adsubcat.name AS subcatname, adsubcat.linkname AS subcatlink,
  adcat.id AS catid, adsubcat.id AS subcatid, ads.r_option AS r_option, ads.R_rand AS R_rand, 
  adcat.catcol1 AS catcol1, adcat.catcol2 AS catcol2, search_town.townId,ads.townId');
  $this->db->from('ads');
  $this->db->join('adsubcat', 'adsubcat.id=ads.subcatid');
  $this->db->join('adcat', 'adcat.id=ads.catid');
  $this->db->join('search_town', 'search_town.townId=ads.townId');
  $this->db->join('search_region', 'search_region.regionId=search_town.relRegionId');
  $this->db->join('search_prov', 'search_prov.provId=search_region.relProvId');
  $this->db->join('ad_image', 'ad_image.adid=ads.id');
  $array = array(
  'ad_image.picorder'=> 1,
  'ad_image.aproved'=> 1,
    'adcat.id' => 9,
   'scam' => 0,
    'adactive' => 1
    );

  $this->db->where($array);
  $this->db->group_by("ads.id");
  $this->db->order_by('addate','desc');
  $this->db->limit(5); 
  $query = $this->db->get(); 
  return $query->result_array();
}

我的 Controller 如下所示:

class Categories extends CI_Controller {
          public function __construct()
          {
                parent::__construct();
                $this->load->model('categorylist_model');
                $this->load->helper('text');
          }
            public function index()
            {
            $this->load->helper('url');
            $data = array('sitename'=>'Title', 'page_title' => 'Categories');
          $data['categories'] = $this->categorylist_model->get_categoryads();
          $this->load->view('templates/header', $data);
            $this->load->view('templates/navbar');
            $this->load->view('templates/breadcrumbs');
            //$this->load->view('templates/category_selector');
            $this->load->view('content_categories');
            $this->load->view('templates/footer');
          }
}

我现在不确定如何将额外的查询添加到 Controller ?或者我应该将其添加到模型本身中以及如何添加?

我尝试将功能添加到 Controller ,如下所示(不正确):

class Categories extends CI_Controller {
          public function __construct()
          {
                parent::__construct();
                $this->load->model('categorylist_model');
                $this->load->helper('text');
          }
            public function index()
            {
            $this->load->helper('url');
            $data = array('sitename'=>'Title', 'page_title' => 'Categories');
          $data['categories'] = $this->categorylist_model->get_categoryads();
          $this->load->view('templates/header', $data);
            $this->load->view('templates/navbar');
            $this->load->view('templates/breadcrumbs');
            //$this->load->view('templates/category_selector');
            $this->load->view('content_categories');
            $this->load->view('templates/footer');
          }
          public function tLink( $aid ) {  
          $ci=& get_instance();
          $ci->load->database(); 

          $sql ="SELECT adfields.f_value AS fvalue FROM adfields
                JOIN field_name ON field_name.id=adfields.f_id
                WHERE adid='$aid' GROUP BY adfields.f_id ORDER BY field_name.keyf ASC"; 

          $query = $ci->db->query($sql);
          $row = $query->row();
          return $row->fvalue;
          }

}

并在 with tLink($adid) 中调用它,但给了我 fatal error :调用未定义的函数 tLink()

最佳答案

评论中提到的 PHP 错误是正确的,或者您是:

  • $aid 传递数组而不是字符串 例如,您传递的是 array( 0 => 45 ) 而不是 45

  • 尝试回显结果,该结果是一个数组/对象。相反,请使用 Code Igniter 的 row()命令,然后挑选您需要的结果。

<小时/>
function tLink( $aid ) {  
    $ci=& get_instance();
    $ci->load->database(); 

    $sql ="SELECT adfields.f_value AS fvalue FROM adfields
          JOIN field_name ON field_name.id=adfields.f_id
          WHERE adid='$aid' GROUP BY adfields.f_id ORDER BY field_name.keyf ASC"; 

    $query = $ci->db->query($sql);
    $row = $query->row();
    return $row->fvalue;
}

最后,最好在 Controller 中加载此模型,而不是在 helper 中需要它(通常用于 View 函数)

/**
 *
**/
class Link_model extends CI_Model { 

    public function getLink( $aid ) { 
          $sql ="SELECT adfields.f_value AS fvalue FROM adfields
                 JOIN field_name ON field_name.id=adfields.f_id
                 WHERE adid='$aid' GROUP BY adfields.f_id ORDER BY
                 field_name.keyf ASC"; 

         $query = $ci->db->query($sql);
         $row = $query->row();
         return $row->fvalue;
    }
}
<小时/>
/**
 *
**/
class Categories extends CI_Controller {

    public function index() {
        $this->load->model( 'Link_model' );

        $categories = array();
        $getCategoryIds = $this->categorylist_model->get_categoryads();

        foreach( $getCategoryIds as $aid ){
             $categories = array(
                 "id"   => $aid,
                 "link" => $this->link_model->getLink( $aid )
             );
        }

        $data = array(
            "categories" => $categories
        );

        $this->load->view('templates/header', $data );
    }

}
<小时/>

现在终于在你看来:

<div class="container">
    <?php if ( isset( $categories ) && count( $categories ) > 0 ): ?>
        <?php foreach( $categories as $category ): ?>
            <?=( $category["link"] )?>
        <?php endforeach; ?>
    <?php endif; ?>
</div>

关于php - 在帮助文件 Codeigniter 3 中查询数据库,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/32458456/

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