php - 在 PHP 中动态检查来自 MySQL 的动态复选框

Question

我有一些动态创建的复选框，使用 PHP 的这段代码创建:

<?php do { ?>
<input type="checkbox" name="Cat_Ref_Array[]" value="<?php echo $row_selectCategories['Cat_Ref']; ?>" />
<label for="Category"><?php echo $row_selectCategories['Category']; ?></label>
<?php } while ($row_selectCategories = mysql_fetch_assoc($selectCategories)); ?>

我还有另一个表，其中保存了可能的响应，其检索方式如下:

$query_getFeatureCat = sprintf("SELECT `Ref`, Cat_Ref, dist FROM newtable WHERE `Ref` = %s", GetSQLValueString($colname_getFeatureCat, "text"));
$getFeatureCat = mysql_query($query_getFeatureCat, $db) or die(mysql_error());
$row_getFeatureCat = mysql_fetch_assoc($getFeatureCat);

当复选框 value 出现在 newtable 查找的输出中时，如何让表单预填充/“选中”复选框？

Answer 1

试试这个

<?php
$query_getFeatureCat = sprintf("SELECT `Ref`, Cat_Ref, dist FROM newtable WHERE `Ref` = %s", GetSQLValueString($colname_getFeatureCat, "text"));
$getFeatureCat = mysql_query($query_getFeatureCat, $db) or die(mysql_error());
$row_getFeatureCat = mysql_fetch_assoc($getFeatureCat);
while ($row_selectCategories = mysql_fetch_assoc($selectCategories)) {
  if ($row_getFeatureCat) {
    if (in_array($row_selectCategories['Cat_Ref'], $row_getFeatureCat)) {
      $checked = 'checked';
    } ?>
  }
  <input type="checkbox" name="Cat_Ref_Array[]" value="<?php echo $row_selectCategories['Cat_Ref']; ?>"  <?php echo $checked; ?>/>
  <label for="Category"><?php echo $row_selectCategories['Category']; ?></label>
<?php }  ?>