MySQL - 提取日期时间并转换为矩阵映射

Question

我有大量的MySQL记录数据，必须像这样转换:

我的问题是，如何提取日期时间值(月、周、小时)并将其插入具有二进制值(0 或 1)的精确列中，如上图所示。

问题已解决，我刚刚找到了最简单的方法，例如:

UPDATE TABLE
SET h1 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '1' THEN 1 
         ELSE '0'
         END
, h2 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '2' THEN '1' 
         ELSE '0' 
         END
, h3 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '3' THEN '1' 
         ELSE '0' 
         END
, h4 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '4' THEN '1' 
         ELSE '0' 
         END
, h5 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '5' THEN '1' 
         ELSE '0' 
         END
, h6 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '6' THEN '1' 
         ELSE '0' 
         END
, h7 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '7' THEN '1' 
         ELSE '0' 
         END
         ;

Answer 1

问题已解决，我刚刚找到了最简单的方法，例如:

UPDATE TABLE
SET h1 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '1' THEN 1 
         ELSE '0'
         END
, h2 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '2' THEN '1' 
         ELSE '0' 
         END
, h3 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '3' THEN '1' 
         ELSE '0' 
         END
, h4 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '4' THEN '1' 
         ELSE '0' 
         END
, h5 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '5' THEN '1' 
         ELSE '0' 
         END
, h6 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '6' THEN '1' 
         ELSE '0' 
         END
, h7 = CASE WHEN (SELECT DAYOFWEEK (trx_datetime)) = '7' THEN '1' 
         ELSE '0' 
         END
         ;