mysql - 将2行合并为一行，使用2列MYSQL

Question

我有一个看起来像这样的表: Table

但是，问题在于，Patricia 有 13 张票和 1 张电影票在同一行，而是分成不同的行。

我认为我需要做一个数据透视表，但我不确定我到底需要做什么。

这是我到目前为止的代码:

    select customer.hippcode, customer.LastName, customer.Firstname, customer.Email,
count(ticketdetails.eventtype) as 'Theater Tickets',
0 as 'Movie Tickets'
from customer
inner join ticketdetails on ticketdetails.hippcode = customer.hippcode
where ticketdetails.hippcode is not null
and ticketdetails.eventType ='T'
Group by Customer.hippcode
union 
select customer.hippcode, customer.LastName, customer.Firstname, customer.Email,
0, count(ticketdetails.eventtype) as 'Movie Tickets'
from customer
inner join ticketdetails on ticketdetails.hippcode = customer.hippcode
where ticketdetails.hippcode is not null
and ticketdetails.eventType ='M'
Group by Customer.hippcode
order by `theater tickets` + `movie tickets` desc;

感谢您提前提供的帮助。

Answer 1

你可以尝试这样的事情:

select 
    customer.hippcode, customer.LastName, customer.Firstname, customer.Email,
    count(case when ticketdetails.eventtype = 'T' then 1 else 0 end) as TheaterTickets,
    count(case when ticketdetails.eventtype = 'M' then 1 else 0 end) as MovieTickets
from customer
inner join ticketdetails on ticketdetails.hippcode = customer.hippcode
where ticketdetails.hippcode is not null
and ticketdetails.eventType in ('T', 'M')
Group by customer.hippcode, customer.LastName, customer.Firstname, customer.Email
Order by TheaterTickets+MovieTickets desc;