php - 根据日期在不同的表中显示数据

Question

我做了一个查询，其中显示了登录电子邮件 ID 的宝贵购买数据。我已经成功地做到了这一点。现在我想根据日期显示数据。这里它显示每行的日期。有什么建议请!!

代码

<h3>My Orders</h3>
<table border="1">
<?php
 $query="select orders.date,order_detail.quantity,order_detail.price,order_detail.color,order_detail.size,customers.name,products.product_name,products.product_image from order_detail JOIN orders on orders.serial=order_detail.orderid Join customers on customers.serial=orders.customerid Join products on products.productid=order_detail.productid where customers.email='$email'";
    $sql=mysqli_query($con,$query);
     while($row=mysqli_fetch_array($sql))
                {
                  ?>
      <tr>
      <td><?php echo $row['date'] ?></td>
      <td><image width="80px" height="90px" src="images/images/<?php echo $row['product_image'] ?>"/></td>
       <td><?php echo $row['product_name']. "*". $row['quantity']?></td>
       <td><?php echo $row['color'] ?></td>
       <td><?php echo $row['price'] ?></td>
       <td><?php echo $row['size'] ?></td>
               </tr>
                <?php
                }
                ?>
        </table> 

Answer 1

您是否尝试过根据日期对它们进行排序？通过添加“ORDER BY column ASC”来增加值或添加“ORDER BY column DESC”来减少值，可以轻松完成此操作!

$query="SELECT orders.date, order_detail.quantity, order_detail.price, 
    order_detail.color, order_detail.size, 
    customers.name, 
    products.product_name, 
    products.product_image 

    FROM order_detail 
    JOIN orders ON orders.serial=order_detail.orderid 
    JOIN customers ON customers.serial=orders.customerid 
    JOIN products ON products.productid=order_detail.productid 
    WHERE customers.email='$email'
    ORDER BY orders.date";

看看manual

如果您想将相同的日期分组在一起，请尝试使用 GROUP BY 命令(如果orders.date 的类型为 DATE/DATETIME/TIMESTAMP，则此示例有效):

$query="SELECT orders.date, order_detail.quantity, order_detail.price, 
    order_detail.color, order_detail.size, 
    customers.name, 
    products.product_name, 
    products.product_image 

    FROM order_detail 
    JOIN orders ON orders.serial=order_detail.orderid 
    JOIN customers ON customers.serial=orders.customerid 
    JOIN products ON products.productid=order_detail.productid 
    WHERE customers.email='$email'
    GROUP BY DATE( orders.date )
    ORDER BY orders.date";

如果您使用 PHP 时间戳或 INT，则需要像这样转换日期:GROUP BY DATE( FROM_UNIXTIME(orders.date ) )。

DATE(col) 将日期/日期时间/时间戳转换为单日。 GROUP BY 将具有相同 DATE 的所有行放入一行。现在您可能还想将显示的数据更改为 SUM(order_detail.price) 以获取当天的总价，依此类推。