php - Mysql复杂排序

Question

我有一个这样的查询

SELECT videos.*, 
       (SELECT COUNT(comment_id) 
        FROM comments 
        WHERE comments.comments_video_id = videos.id) AS video_comments
FROM videos
ORDER BY video_comments DESC

现在，如果我有 2 行具有相同的“videos_comments”计数，如何编写此代码，以便在这两个视频之间，首先显示评论表中具有最新评论 (comments_date) 的视频

Answer 1

SELECT videos.id, count(*) video_comments 
FROM videos LEFT JOIN comments 
ON comments.comments_video_id = videos.id
GROUP BY videos.id
ORDER BY video_comments DESC