php - 在php中从数组中获取结果

标签 php mysql arrays

我有一个像这样的数组,它是数据库选择操作的结果。

Array
(
    [0] => Array
        (
            [id] => 1
            [name] => shamonsha
            [username] => sham1s670
            [password] => 5hYZJPu3s/oAE7KbFfgsvQfX4/GCvnK1MpR0bIbWWxroUgLb+E3M7/AFyJNcZ9WirkAGCe6JBofh54dOPENdrg==
            [email] => shamonsha665@gmail.com
            [mobile_number] => 7736527089
            [address] => hk
            [date] => 24 Dec 2015 01:32:53
            [active] => 1
            [commission] => 25
            [agent_id] => 1
            [ticket_number] => ETS263B0PT10469
            [refund_amount] => 700
            [date_of_cancel] => 28-Jan-2016
        )

    [1] => Array
        (
            [id] => 2
            [name] => shamonsha
            [username] => sham1s670
            [password] => 5hYZJPu3s/oAE7KbFfgsvQfX4/GCvnK1MpR0bIbWWxroUgLb+E3M7/AFyJNcZ9WirkAGCe6JBofh54dOPENdrg==
            [email] => shamonsha665@gmail.com
            [mobile_number] => 7736527089
            [address] => hk
            [date] => 24 Dec 2015 01:32:53
            [active] => 1
            [commission] => 25
            [agent_id] => 1
            [ticket_number] => ETS311B0PT10470
            [refund_amount] => 700
            [date_of_cancel] => 28-Jan-2016
        )

    [2] => Array
        (
            [id] => 3
            [name] => shamonsha
            [username] => sham1s670
            [password] => 5hYZJPu3s/oAE7KbFfgsvQfX4/GCvnK1MpR0bIbWWxroUgLb+E3M7/AFyJNcZ9WirkAGCe6JBofh54dOPENdrg==
            [email] => shamonsha665@gmail.com
            [mobile_number] => 7736527089
            [address] => hk
            [date] => 24 Dec 2015 01:32:53
            [active] => 1
            [commission] => 25
            [agent_id] => 1
            [ticket_number] => ETS788B0PT10472
            [refund_amount] => 395
            [date_of_cancel] => 28-Jan-2016
        )

    [3] => Array
        (
            [id] => 4
            [name] => shamonsha
            [username] => sham1s670
            [password] => 5hYZJPu3s/oAE7KbFfgsvQfX4/GCvnK1MpR0bIbWWxroUgLb+E3M7/AFyJNcZ9WirkAGCe6JBofh54dOPENdrg==
            [email] => shamonsha665@gmail.com
            [mobile_number] => 7736527089
            [address] => hk
            [date] => 24 Dec 2015 01:32:53
            [active] => 1
            [commission] => 25
            [agent_id] => 1
            [ticket_number] => ETS562B0PT10471
            [refund_amount] => 395
            [date_of_cancel] => 28-Jan-2016
        )

    [4] => Array
        (
            [id] => 5
            [name] => shamonsha
            [username] => sham2s7b8
            [password] => dN0Br+3D86pGTAhlvOJ4OD6YH1KVHL/SkfYOu71Do7OCxrRnMIq9CLVWX7mpTnJso1pYxVwvjzFWo1a1GVq+8Q==
            [email] => shamonsha665@gmail.com
            [mobile_number] => 7736527089
            [address] => jk
            [date] => 24 Dec 2015 01:33:20
            [active] => 1
            [commission] => 0
            [agent_id] => 2
            [ticket_number] => ETS562B0PT10471
            [refund_amount] => 395
            [date_of_cancel] => 28-Jan-2016
        )

)

从此我想像这样显示每个用户名的ticket_amountrefund_amountdate_of_cancel 例如:

Username:sham1s670
  ticket-no:ETS263B0PT10469 ,refund-amount:700, cancel-data:28-Jan-2016
  ticket-no:ETS263B0PT10461 ,refund-amount:500, cancel-data:28-Jan-2016
  ticket-no:ETS263B0PT10462 ,refund-amount:200, cancel-data:28-Jan-2016

Username:sham1s674
  ticket-no:ETS263B0PT10462 ,refund-amount:700, cancel-data:28-Jan-2016
  ticket-no:ETS263B0PT10468 ,refund-amount:600, cancel-data:28-Jan-2016
  ticket-no:ETS263B0PT10469 ,refund-amount:200, cancel-data:28-Jan-2016

这是我尝试过的代码

$i=0;
foreach($result as $value)
{
    $old = $value['username'];
    if($old==$value['username'])
    {
        if($i==0){
            echo 'Username'.$value['username'];
            echo '<br>';
        }
        echo "TIcket-no".$value['ticket_number'].'Refund-amound'.$value['refund_amount'].'Cancel-date'.$value['date_of_cancel'];

        $i++;
    }
    else
    {
        $old='';
        $i=0;
    }
}

但是它没有给我预期的结果?

最佳答案

它没有给出期望的结果,因为 $old 永远不会像 $value['username'] (你永远不会启动它),因此总是触发 else 选项。

您必须重写查询并按用户分组,或者在解析结果后对结果进行排序,以将用户与票证相匹配

未经测试:

<?php

  $data = array();
  $output = false;

  // this first foreach could be done on db fetch rows instead
  foreach ( $result as $value ) {

      $data[$value['username']][] = 'TIcket-no ' . $value['ticket_number'] . ', Refund-amound ' . $value['refund_amount'] . ', Cancel-date ' . $value['date_of_cancel'];

  }

  foreach( $data as $username => $list ) {

    $output .= '<p>Username ' . $username . '<br>';
    $output .= implode( '<br>', $list );
    $output .= '</p>';

  }

  echo $output;

?>

** 根据请求更新 **

添加用户名(尚未测试)

<?php

  $data = array();
  $output = false;

  // this first foreach could be done on db fetch rows instead
  foreach ( $result as $value ) {

      if ( !isset( $data[$value['username']]['name'] ) ) {
        $data[$value['username']]['name'] = $value['name'];
      }
      $data[$value['username']]['data'][] = 'TIcket-no ' . $value['ticket_number'] . ', Refund-amound ' . $value['refund_amount'] . ', Cancel-date ' . $value['date_of_cancel'];

  }

  foreach( $data as $username => $dataset ) {

    $output .= '<p>Name: ' . $dataset['name'] . '<br>';
    $output .= 'Username: ' . $username . '<br>';
    $output .= implode( '<br>', $dataset['data'] );
    $output .= '</p>';

  }

  echo $output;

?>

关于php - 在php中从数组中获取结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35067100/

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