我想将从网络服务器接收到的回显消息转换为字符串，我想将其与onPostExecute中的另一个字符串进行比较 方法。 当输入正确的值时，仅显示 onPostExecute 的 else 部分。为什么这样？我应该怎么做才能解决这个问题？
@Override
public String doInBackground(String... params) {
//String reg_url="http://127.0.0.1//webapp/Register.php";
String reg_url="http://10.0.2.2/webapp/Register.php";
String login_url="http://10.0.2.2/webapp/login.php";
String method= params[0];
if(method.equals("register"))
{
String name=params[1];
String u_address=params[2];
String user_pass=params[3];
String u_email=params[4];
String u_zip=params[5];
String u_mob=params[6];
try {
URL url = new URL(reg_url);
HttpURLConnection httpURLConnection=(HttpURLConnection)url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
OutputStream os = httpURLConnection.getOutputStream();
BufferedWriter bufferedWriter= new BufferedWriter(new OutputStreamWriter(os,"UTF-8"));
String data = URLEncoder.encode("user","UTF-8")+"="+URLEncoder.encode(name,"UTF-8")+"&"+
URLEncoder.encode("address","UTF-8")+"="+URLEncoder.encode(u_address,"UTF-8")+"&"+
URLEncoder.encode("user_pass","UTF-8")+"="+URLEncoder.encode(user_pass,"UTF-8")+"&"+
URLEncoder.encode("emailid","UTF-8")+"="+URLEncoder.encode(u_email,"UTF-8")+"&"+
URLEncoder.encode("zip","UTF-8")+"="+URLEncoder.encode(u_zip,"UTF-8")+"&"+
URLEncoder.encode("mob","UTF-8")+"="+URLEncoder.encode(u_mob,"UTF-8");
bufferedWriter.write(data);
bufferedWriter.flush();
bufferedWriter.close();
os.close();
BufferedReader bufferedReader= new BufferedReader(new InputStreamReader(httpURLConnection.getInputStream()));
String result;
result = bufferedReader.readLine();
// / InputStream is= httpURLConnection.getInputStream();
// is.close();
// return "Registration Success...";
return result.toString();
}
catch(Exception e)
{
return null;
}
/*catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}*/
}
else {
if (method.equals("login")) {
String login_name = params[1];
String login_pass = params[2];
try {
URL url = new URL(login_url);
HttpURLConnection httpURLConnection=(HttpURLConnection)url.openConnection();
httpURLConnection.setRequestMethod("POST");
httpURLConnection.setDoOutput(true);
httpURLConnection.setDoInput(true);
OutputStream os = httpURLConnection.getOutputStream();
BufferedWriter bufferedWriter= new BufferedWriter(new OutputStreamWriter(os,"UTF-8"));
String data = URLEncoder.encode("login_name","UTF-8")+"="+URLEncoder.encode(login_name,"UTF-8")+"&"+
URLEncoder.encode("login_pass","UTF-8")+"="+URLEncoder.encode(login_pass,"UTF-8");
bufferedWriter.write(data);
bufferedWriter.flush();
bufferedWriter.close();
os.close();
InputStream inputStream=httpURLConnection.getInputStream();
BufferedReader bufferedReader= new BufferedReader(new InputStreamReader(inputStream,"iso-8859-1"));
String response="";
String line="";
while ((line=bufferedReader.readLine())!=null)
{
response+=line;
}
bufferedReader.close();
inputStream.close();
httpURLConnection.disconnect();
return response.toString();
}
/* catch(Exception e)
{
return null;
} */
catch (MalformedURLException e) {
e.printStackTrace();
} catch (ProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
}
}
return null;
}
我正在尝试比较从服务器返回的回显响应，该响应又返回到 onPostExecute 方法，如下所示
protected void onPostExecute(String s) {
/* if(result.equals("Registration Success...")){
Toast.makeText(ctx,result,Toast.LENGTH_LONG).show();
}
else{
//if(result.equals("Login Success...")){
// Toast.makeText(ctx,"Login Success!",Toast.LENGTH_LONG).show();
alertDialog.setMessage(result);
alertDialog.show();
}
/*else
{
Toast.makeText(ctx,"Failed!",Toast.LENGTH_LONG).show();
} */
/* if(method.equals("login"))
{ */
loading.dismiss();
if(s.equals("Login Success..."))
{
Intent intent = new Intent(ctx,MainActivity.class);
// intent.putExtra("USER_NAME",login_name);
ctx.startActivity(intent);
}
/* else{
Toast.makeText(ctx,result,Toast.LENGTH_LONG).show();
}
}
else if(method.equals("register")) {
*/
else if (s.equals("Registered Successfully")){
Intent intent = new Intent(ctx,Login.class);
ctx.startActivity(intent);
}
else{
Toast.makeText(ctx,s,Toast.LENGTH_LONG).show();
}
// }
}
最佳答案
确保回显消息位于上面的代码中。 我建议创建一个字符串变量并将其等同于回显消息。喜欢:
字符串 serverResponseText = new String(serveResponse.toString());
这应该可以解决你的问题。祝你好运
关于php - 如何将 Echo 消息从 php 转换为字符串进行比较？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36232431/