我有两个表,一个是random_questions,另一个是personal_questions,我想检查personal_questions中的copy_id列,其中personal_questions.question_to = current_session_user
和personal_question.copy_id = random_question.id
....
这是我的代码:
$session_user = $_SESSION['user_id'];
$sql = mysqli_query($con, "SELECT DISTINCT random_questions.id AS id, random_questions.question_by_id AS question_by_id, random_questions.question AS question, random_questions.total_answers AS answers FROM random_questions INNER JOIN personal_questions WHERE (random_questions.total_answers != '8') OR (personal_questions.question_to != '$session_user' AND personal_questions.copy_id != random_questions.id)");
我没有正确得到结果,如果personal_questions的copy_id等于任何random_questions的id,那么结果会自动重复。我希望你明白。请帮助。
最佳答案
Select *
from random_questions p,
personal_questions a
where a.question_to = current_session_user
and a.copy_id = p.id;
关于php - 如何准备查询以从另一个表检查然后从另一个表获取,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/36821836/