我正在尝试创建一个简单的数据库，它需要姓名、出生日期等。我使用 HTML 表单从用户那里获取数据，如下所示:
<!DOCTYPE html>
<head>
<title>BIODATA</title>
</head>
<style>
form{
width:500px;
margin: 0 auto;
}
</style>
<body>
<h1><b><center>ASSIGNMENT Operating Systems Lab</center></b></h1>
<h2><b><center><u>BIODATA</u></center></b></h2>
<h3><b><center>Roll no : EPANECS042</center></b></h3>
<br>
<br>
<br>
<form action="bio.php" method="post" >
First name:<br>
<input type="text" name="firstname">
<br>
Last name:<br>
<input type="text" name="lastname">
<br>
Mother's Name:<br>
<input type="text" name="mothername">
<br>
Father's name:<br>
<input type="text" name="fathername">
<br><br>
Date of Birth:<br>
Day<input type="number" name="day" min="1" max="31">
Month<input type="number" name="month" min="1" max="12">
Year<input type="number" name="year" min="1990" max="2050">
<br><br>
<input type="radio" name="gender" value="male" checked> Male<br>
<input type="radio" name="gender" value="female"> Female<br>
<input type="radio" name="gender" value="other"> Other<br>
<br>
<input type="submit" value="Submit">
</form>
</body>
</html>
我使用php将数据输入到MySQL数据库。为此，我使用文件 bio.php 插入数据，并使用 DbConnect.php 连接到数据库。
bio.php
<?php
include_once './DbConnect.php';
function createNewBio() {
$response = array();
$FirstName = $_POST["firstname"];
$LastName = $_POST["lastname"];
$MothersName = $_POST["mothername"];
$FathersName = $_POST["fathersname"];
$Gender = $_POST["gender"];
$Day = $_POST["day"];
$Month = $_POST["month"];
$Year = $_POST["year"];
//combining variables
$Name = $FirtsName.$LastName;
$DOB = strval($Day).strval($Month).strval($Year);
$Query = "INSERT INTO biodata VALUES ({$Name},{$MothersName},{$FathersName}, {$DOB},{$Gender})";
$Result = mysql_query($Query) or die(mysql_error());
if ($result) {
$response["error"] = false;
$response["message"] = "Registered Successfully!!";
$response["ID"] = $id;
} else {
$response["error"] = true;
$response["message"] = "Registration unsuccessfull!!";
}
echo json_encode($response);
}
createNewBio();
?>
DbConnect.php
<?php
class DbConnect {
private $conn;
function __construct() {
//connecting to database
$this->connect();
}
function __destruct() {
$this->close();
}
function connect() {
$this->conn = mysql_connect('127.0.0.1', 'root','') or die(mysql_error());
mysql_select_db('assignment') or die(mysql_error());
// returing connection resource
echo $this->conn;
return $this->conn;
}
// Close function
function close() {
// close db connection
mysql_close($this->conn);
}
}
?>
问题是我无法上传数据。我用的是wamp当我在浏览器中打开 bio.php 时，我得到以下信息:
Notice: Undefined index: firstname in C:\xampp\htdocs\bio.php on line 5
Notice: Undefined index: lastname in C:\xampp\htdocs\bio.php on line 6
Notice: Undefined index: mothername in C:\xampp\htdocs\bio.php on line 7
Notice: Undefined index: fathersname in C:\xampp\htdocs\bio.php on line 8
Notice: Undefined index: gender in C:\xampp\htdocs\bio.php on line 9
Notice: Undefined index: day in C:\xampp\htdocs\bio.php on line 10
Notice: Undefined index: month in C:\xampp\htdocs\bio.php on line 11
Notice: Undefined index: year in C:\xampp\htdocs\bio.php on line 12
Notice: Undefined variable: FirtsName in C:\xampp\htdocs\bio.php on line 15
No database selected
我没明白哪里出了问题？请帮忙。
最佳答案
注意: undefined index 信息，您应该在调用时使用 if 条件包装 createNewBio() 函数，例如:
if (isset($_POST['submit'])) {
//Run the function inside this
createNewBio();
}
未选择数据库，请尝试:
$con = mysql_connect('xxx', 'xxx', 'xxx') or die (mysql_error());
$db = mysql_select_db("database", $con);
另外，尽量避免使用 mysql，因为它已被弃用，请使用 mysqli 代替:)
关于php - 无法将数据上传到 wamp localhost 中的数据库，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/36950863/