java - 获取 http 响应 PHP 和 ANDROID

Question

我正在尝试获取 HTTP 响应。它在客户端不起作用。 尝试通过“ postman ”获得回复，并且成功了。

1. 我确信 PHP 方面一切正常。
2. 可能是因为类已被弃用。

Android 代码:`

            //Connect to mysql.
            HttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost("www.example.com/register.php");

            //JSON object.
            JSONObject jsonObject = new JSONObject();
            jsonObject.put("username", register_username);
            jsonObject.put("password", register_password);

            //Entity builder to send value.
            EntityBuilder entityBuilder = EntityBuilder.create();
            entityBuilder.setText(jsonObject.toString());
            httpPost.setEntity(entityBuilder.build());

            //Getting response
            HttpResponse response = httpClient.execute(httpPost);
            String responseBody = EntityUtils.toString(response.getEntity());
            //When I try to print it out, I get value of "org.apache.http.message.BasicHttpResponse@32857430"`

PHP 代码:`

JSON EXAMPLE:
<?php
$con=mysqli_connect("localhost","tx","xxx","txxxt");

$data = json_decode(file_get_contents('php://input'));
$username = $data->{'username'};
$password = $data->{'password'};


$query = mysqli_query($con, "SELECT * FROM user WHERE username='$username'");

if(mysqli_num_rows($query) > 0){
$response = new stdClass();
$response->status="Already exists";
$response->code=0;
echo json_encode($response );}

else{
$response = new stdClass();
$response->status="Registered";
$response->code=1;
echo json_encode($response );

$sql_query = "insert into user values('$username','$password', 'null', 'null' ,'null');";
mysqli_query($con, $sql_query) or die (mysqli_error($con));

}


mysqli_close($con);
?>

`

如有任何帮助，我们将不胜感激!

Answer 1

我设法解决了这个问题:

WHAT I DID WRONG:

   //JSON object.
            JSONObject jsonObject = new JSONObject();
            jsonObject.put("username", register_username);
            jsonObject.put("password", register_password);

            //Entity builder to send value.
            EntityBuilder entityBuilder = EntityBuilder.create();
            entityBuilder.setText(jsonObject.toString());
            httpPost.setEntity(entityBuilder.build());

            //Getting response
            HttpResponse response = httpClient.execute(httpPost);
            String responseBody = EntityUtils.toString(response.getEntity());
            JSONObject responseObject = new JSONObject(responseBody);

WHAT I DID TO FIX

  //JSON object.
            JSONObject jsonObject = new JSONObject();
            jsonObject.putOpt("username", register_username);
            jsonObject.putOpt("password", register_password);

            //Entity builder to send value.
            EntityBuilder entityBuilder = EntityBuilder.create();
            entityBuilder.setText(jsonObject.toString());
            httpPost.setEntity(entityBuilder.build());

            //Getting response
            HttpResponse response = httpClient.execute(httpPost);
            String responseBody = EntityUtils.toString(response.getEntity());
            JSONObject responseObject = new JSONObject(responseBody);

不知道为什么，但 putOpt 方法以某种方式修复了它。如果您知道原因，请随时回复。