我遇到了类似的错误。
未捕获的 PDOException:SQLSTATE[21000]:基数违规:1241 操作数应包含 1 列
if ($_POST['submit'] ?? '' == "Log In") {
$query = "SELECT * FROM member WHERE (email, password) LIKE (:email, :password)";
$stmt = $link -> prepare($query);
$stmt -> bindValue(':email', $_POST['loginemail'], PDO::PARAM_STR);
$stmt -> bindValue(':password', md5(md5($_POST['loginemail']).$_POST['loginpassword']), PDO::PARAM_STR);
$stmt -> execute();
$rows = $stmt -> fetchAll();
}
但是这个语句没有错误。
$sql = "SELECT ko_name FROM dogBREEDS WHERE dogBREEDS.ko_name LIKE (:keyword) ORDER BY id ASC LIMIT 0, 10";
$query = $pdo->prepare($sql);
$query->bindParam(':keyword', $keyword, PDO::PARAM_STR);
$query->execute();
$list = $query->fetchAll();
我该如何解决这个问题?和有什么区别??
最佳答案
$query = "SELECT * FROM member WHERE (email, password) LIKE (:email, :password)";
此 sql 的语法不正确。 LIKE
(或者看看这里 MySQL LIKE Clause )不能这样使用,请尝试这个;)
$query = "SELECT * FROM member WHERE email LIKE (:email) and password LIKE (:password)";
关于mysql - 未捕获的 PDOException : SQLSTATE[21000]: Cardinality violation: 1241 Operand should contain 1 column(s),我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/37236235/