php - MySqli 准备好的语句在执行语句时不使用更新的变量值

Question

我准备好的语句在执行时没有使用更新的值，而是使用我在绑定(bind)之前设置的值，这是它应该如何工作的吗？因为在 w3schools 的示例中它使用的是更新值，所以我不确定我在这里做错了什么，在//winner comment is Problems 部分下，$assqlst2 没有使用 $pointswon 的更新值(我把 echo 只是确保值正确，并且我在输出中没有收到任何错误)。

<?php 
$dbserver = ""; //database information is populated in my script, i didn't put it here because of security resons.
$dbusername = "";
$dbpassword = "";
$dbname = "";  
$dbrecievedPassword = $_POST['dbPassword'];
$winnerid = intval($_POST['winnerid']);
$winnername = $_POST['winnername'];
$pointswon = intval($_POST['pointswon']);
$loserid = intval($_POST['loserid']);
$losername = $_POST['losername'];
$pointsph = $pointswon;
if($dbrecievedPassword != null && $dbrecievedPassword == $dbpassword) {
    echo "PWD_OK";
}
else {
    echo "PWD_INCORRECT";
}

$conn = new mysqli($dbserver,$dbusername,$dbrecievedPassword);
mysqli_select_db($conn,$dbname);
if($conn->connect_error) {
    die("Connection failed: ".connect_error);
}
if($winnerid != null) {
    if($sqlst = $conn->prepare("SELECT * FROM table_name WHERE uid=?")) {
        if($assqlst2 = $conn->prepare("UPDATE table_name SET as_points=? WHERE as_uid=?")) {
            if($sqlst3 = $conn->prepare("INSERT INTO table_name (as_uid,as_points,as_username) VALUES (?,?,?)")) {

                $sqlst->bind_param("i",$winnerid);
                $assqlst2->bind_param("ii",$pointswon,$winnerid);

                $sqlst3->bind_param("iis",$winnerid,$pointswon,$winnername);
                if($loserid != null) {
                    //winner

                    if(!$sqlst->execute()) {
                        echo $conn->error;
                    }
                    $sqlst->bind_result($b1,$b2,$b3);
                    $sqlst->fetch();
                    $pointswon = $pointsph + intval($b3);
                    echo $pointswon." ".$winnerid;
                    if(!$assqlst2->execute()) {
                        echo $conn->error;
                    }
                    //loser
                    $winnerid = $loserid;
                    if(!$sqlst->execute()) {
                        echo $conn->error;
                    }
                    $sqlst->bind_result($c1,$c2,$c3);
                    $sqlst->fetch();
                    $pointswon = intval($c3) - $pointsph;
                    $sqlst->close();
                    if(!$assqlst2->execute()) {
                        echo $conn->error;
                    }
                    $assqlst2->close();

                }else {
                    if(!$sqlst->execute()) {
                        echo $conn->error;
                    }
                    $sqlst->bind_result($k1,$k2,$k3);
                    $sqlst->fetch();
                    if($k1 != null) {
                        $pointswon = intval($pointsph) + intval($k3);
                        $sqlst->close();
                        if(!$assqlst2->execute()) {
                            echo $conn->error;
                        }
                        $assqlst2->close();

                    }else {
                        $pointswon = $pointsph;
                        $sqlst3->execute();
                        $sqlst3->close();
                    }
                }
            }else {
                echo $conn->error;
            }
        }else {
            echo $conn->error;
        }
    }else {
        echo $conn->error;
    }

}
?>

Answer 1

它真的必须嵌套吗？

您不能只是重新哈希查询并多次使用它。如果你愿意，你只需将它放在一个函数中，这样你只需在需要时调用它即可:

function query1($conn, $winnerid){

    if($sqlst = $conn->prepare("SELECT col1, col2, col3 FROM table_name WHERE uid = ?")){
        $sqlst->bind_param("i", $winnerid);
        $sqlst->execute();
        $sqlst->bind_result($b1, $b2, $b3);
        $sqlst->fetch();
        $sqlst->close();
    }

    return array($b1, $b2, $b3);

}

function query2($conn, $pointswon, $id){

    if($assqlst2 = $conn->prepare("UPDATE table_name SET as_points = ? WHERE as_uid = ?"))
        $assqlst2->bind_param("ii", $pointswon, $id);
        $assqlst2->execute();
        $assqlst2->close();
    }

}

function query3($conn, $winnerid, $pointswon, $winnername){

    if($sqlst3 = $conn->prepare("INSERT INTO table_name (as_uid,as_points,as_username) VALUES (?,?,?)")){
        $sqlst3->bind_param("iis", $winnerid, $pointswon, $winnername);
        $sqlst3->execute();
        $sqlst3->close();
    }

}

设置完功能后，我们就可以继续实现您想要实现的功能了:

if($winnerid != NULL){

    /*** WINNER UPDATE ***/
    list($b1, $b2, $b3) = query1($conn, $winnerid); /* CALL THE SELECT QUERY */

    if($loserid != NULL){
        $pointswon = $pointsph + intval($b3); /* POINTS GATHERED BY THE WINNER */
        echo $pointswon." ".$winnerid;
    } /* END OF CONDITION $loserid IS NOT NULL */

    query2($conn, $pointswon, $winnerid); /* CALL THE UPDATE QUERY */


    /*** LOSER UPDATE ***/
    list($c1, $c2, $c3) = query1($conn, $loserid); /* CALL THE SELECT QUERY */

    $pointswon = intval($c3) - $pointsph; /* POINT GATHERED BY THE LOSER */

    query2($conn, $pointswon, $loserid); /* CALL THE UPDATE QUERY */


} /* END OF CONDITION $winnerid IS NOT NULL */

else {

    list($k1, $k2, $k3) = query1($conn, $winnerid); /* CALL THE SELECT QUERY */

    if($k1 != null){

        $pointswon = intval($pointsph) + intval($k3);

        query2($conn, $pointswon, $winnerid); /* CALL THE UPDATE QUERY */

    } else {

        query3($conn, $winnerid, $pointsph, $winnername); /* CALL THE INSERT QUERY */

    }

} /* END OF ELSE */