我的分页代码从 html 文件中获取页码值，并使用 sql 数据库表中的分页逻辑显示特定页面。 我在这里给出了代码，然后显示了错误。请帮助 .提前致谢!!
<%@ page contentType="text/html; charset=iso-8859-1" language="java" import="java.sql.*" errorPage="" %>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />
<title>Untitled Document</title>
</head>
<body>
<form id="form1" name="form1" method="post" action="">
<table width="100%" border="0" cellpadding="0" cellspacing="0" bgcolor="#CCCCCC">
<tr bgcolor="#66FF99">
<td>Sr.</td>
<td>Name</td>
<td>Cost</td>
</tr>
<%
int p= Integer.parseInt(request.getParameter("textfield"));
Class.forName("com.mysql.jdbc.Driver");
Connection con=DriverManager.getConnection("jdbc:mysql://localhost/tiop","root","root");
Statement stat=con.createStatement();
ResultSet rs=stat.executeQuery("select * From (select * , Row_Number() over (order by Sr) as RowNum From cre )T where T.RowNum between ((p-1)*5)+1
and (p*5)");
while(rs.next())
{
%>
<tr>
<td bgcolor="#99CC33"><%=rs.getInt(1)%></td>
<td bgcolor="#669966"><%=rs.getString(2)%></td>
<td bgcolor="#FF3333"><%=rs.getInt(3)%></td>
</tr>
<%
}
%>
</table>
</form>
</body>
</html>
显示错误:
HTTP Status 500 - Unable to compile class for JSP:
type Exception report
message Unable to compile class for JSP:
description The server encountered an internal error that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: Unable to compile class for JSP:
An error occurred at line: 29 in the jsp file: /pa.jsp
String literal is not properly closed by a double-quote
26: Class.forName("com.mysql.jdbc.Driver");
27: Connection con=DriverManager.getConnection("jdbc:mysql://localhost/tiop","root","root");
28: Statement stat=con.createStatement();
29: ResultSet rs=stat.executeQuery("select * From (select * , Row_Number() over (order by Sr) as RowNum From cre )T where T.RowNum between ((p-1)*5)+1
30: and (p*5)");
31:
32: while(rs.next())
Stacktrace:
org.apache.jasper.compiler.DefaultErrorHandler.javacError(DefaultErrorHandler.java:103)
org.apache.jasper.compiler.ErrorDispatcher.javacError(ErrorDispatcher.java:199)
org.apache.jasper.compiler.JDTCompiler.generateClass(JDTCompiler.java:446)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:361)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:336)
org.apache.jasper.compiler.Compiler.compile(Compiler.java:323)
org.apache.jasper.JspCompilationContext.compile(JspCompilationContext.java:564)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:357)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:405)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:349)
javax.servlet.http.HttpServlet.service(HttpServlet.java:725)
org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
note The full stack trace of the root cause is available in the Apache Tomcat/8.0.9 logs.
Apache Tomcat/8.0.9
最佳答案
无错误证明
解决方案:复制并粘贴以下内容:@Barranka 也是正确的
String query = "select * From (select * , Row_Number() over (order by Sr) as RowNum From cre )T where T.RowNum between ((p-1)*5)+1 and (p*5)";
ResultSet rs = stat.executeQuery(query);
如果您无法将完整的select-query放在一行上。执行以下操作:
ResultSet rs = stat.executeQuery("select * From (select * , Row_Number() over (order by Sr) as RowNum From cre )T where T.RowNum between ((p-1)*5)+1" +
"add (p*5)");
问题出在哪里？
Suggested by StackTrace "String literal is not properly closed by a double-quote"
在下一行的 XXX 标记上。换行导致了这个问题。 and (p*5)" 位于下一行，没有连接。
"select * From (select * , Row_Number() over (order by Sr) as RowNum From cre )T where T.RowNum between ((p-1)*5)+1
XXX and (p*5)"
为了简单起见:将查询存储在字符串中、连接多个查询、简化长查询并在查询执行中使用它们。此外，还有助于重用该查询。
关于java - 我的代码显示错误，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/38129625/