源表:
REFERENCE | DATETIME | AMOUNT | SENDER |RECIPIENT
--------------------------------------------------------------
AAB841 |2016-05-11 14:00:01|200.0000 | SENDER1 |RECIPIENT1
AAB842 |2016-05-11 14:28:05|300.0000 | SENDER2 |RECIPIENT1
AAB868 |2016-05-13 08:15:59|1700.0000| SENDER3 |RECIPIENT1
AAB883 |2016-05-17 13:07:14|1200.0000| SENDER1 |RECIPIENT2
AAB891 |2016-05-30 12:59:16|1200.0000| SENDER2 |RECIPIENT2
AAB892 |2016-05-30 13:10:32|1200.0000| SENDER3 |RECIPIENT2
AAB893 |2016-06-02 10:32:44|1000.0000| SENDER1 |RECIPIENT3
AAB894 |2016-06-02 15:24:58|100.0000 | SENDER2 |RECIPIENT3
AAB895 |2016-06-02 15:33:09|100.0000 | SENDER3 |RECIPIENT3
预期结果: 如果发件人发送超过 2000 个,请选择“记录”
REFERENCE | DATETIME | AMOUNT | SENDER |RECIPIENT
-------------------------------------------------------------
AAB841 |2016-05-11 14:00:01|200.0000 | SENDER1 |RECIPIENT1
AAB883 |2016-05-17 13:07:14|1200.0000| SENDER1 |RECIPIENT2
AAB893 |2016-06-02 10:32:44|1000.0000| SENDER1 |RECIPIENT3
AAB868 |2016-05-13 08:15:59|1700.0000| SENDER3 |RECIPIENT1
AAB892 |2016-05-30 13:10:32|1200.0000| SENDER3 |RECIPIENT2
AAB895 |2016-06-02 15:33:09|100.0000 | SENDER3 |RECIPIENT3
预期结果:
如果发件人发送的内容少于 2000,请选择“记录”
REFERENCE | DATETIME | AMOUNT | SENDER |RECIPIENT
-------------------------------------------------------------
AAB842 |2016-05-11 14:28:05|300.0000 | SENDER2 |RECIPIENT1
AAB891 |2016-05-30 12:59:16|1200.0000| SENDER2 |RECIPIENT2
AAB894 |2016-06-02 15:24:58|100.0000 | SENDER2 |RECIPIENT3
我的初始查询:
select TBL1.REFERENCE, DATE(TBL1.DATETIME), TBL1.AMOUNT, TBL1.DATETIME, TBL1.SENDER, TBL1.RECIPIENT
from SOURCETABLE AS TBL1
WHERE (TBL1.DATETIME >= '2015-05-01 00:00:00' and TBL1.DATETIME <= '2016-07-25 23:59:59' )
GROUP BY DATE(TBL1.DATETIME), TBL1.AMOUNT,TBL1.DATETIME,TBL1.SENDER, TBL1.RECIPIENT
HAVING SUM(TBL1.AMOUNT) > 2000;
--- 0 个结果 ---
但是它不起作用。希望有人能给我关于如何解决问题的见解。
最佳答案
这是一种方法:
select t.*
from sourcetable t
where sender in (select t2.sender
from sourcetable t2
where t2.datetime >= '2015-05-01' and t2.datetime <= '2016-07-26'
group by t2.sender
having sum(t2.amount) > 2000
) and
t.datetime >= '2015-05-01' and t.datetime <= '2016-07-26';
子查询生成满足条件的发件人列表。然后外部查询选择行。
关于mysql - 如何选择金额总和等于某个值并按特定列(发件人或收件人)分组的所有记录?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/38565359/