我正在尝试从 Android Activity 创建一个注册页面，将数据连接到我的 sqldatabase，我收到此错误“org.json.JSONException: Value
首先，有人可以建议我在 Android 应用程序中使用 mysql 数据库和 php 脚本时如何调试我的程序吗？因为我通常使用日志猫，但这里的错误并不那么清楚:S ...
这是 Activity 代码:
public class Subscribe extends Activity {
Button bSubscribe;
EditText etPwdSub, etPwdConf, etLoginSub, etNameSub, etFnSub;
String result = null;
InputStream is = null;
String donnees = "";
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.subscribe);
etLoginSub = (EditText) findViewById(R.id.etLoginSub);
etPwdSub = (EditText) findViewById(R.id.etPwdSub);
etPwdConf = (EditText) findViewById(R.id.etPwdConf);
etNameSub = (EditText) findViewById(R.id.etNameSub);
etFnSub = (EditText) findViewById(R.id.etFnSub);
bSubscribe = (Button) findViewById(R.id.bSubscribe);
bSubscribe.setOnClickListener(new View.OnClickListener() {
public void onClick(View v) {
Pattern p = Pattern.compile(".+@.+\\.[a-z]+");
Matcher m = p.matcher(etLoginSub.getEditableText());
if (m.matches() == false) {
Toast.makeText(
getBaseContext(),
"Le champs email ne correspond pas au format d'une adresse mail",
Toast.LENGTH_SHORT).show();
} else {
// autre méthode : etPwdSub.equals("")
if (etPwdSub.getEditableText() != null
&& etPwdConf.getEditableText() != null
&& etNameSub.getEditableText() != null
&& etFnSub.getEditableText() != null) {
if (etPwdSub.getEditableText().toString().equals(etPwdConf.getEditableText().toString())) {
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
nameValuePairs.add(new BasicNameValuePair("login", etLoginSub.getText().toString()));
nameValuePairs.add(new BasicNameValuePair("pwd", etPwdConf.getText().toString()));
nameValuePairs.add(new BasicNameValuePair("name", etNameSub.getText().toString()));
nameValuePairs.add(new BasicNameValuePair("firstname", etFnSub.getText().toString()));
try {
// commandes httpClient
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost(
"http://192.168.1.101/spotnshare/subscribe.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
} catch (Exception e) {
Log.i("taghttppost", "" + e.toString());
Toast.makeText(getBaseContext(), e.toString(), Toast.LENGTH_LONG)
.show();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "UTF-8"));
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result = sb.toString();
} catch (Exception e) {
Log.i("tagconvertstr", "" + e.toString());
}
try {
JSONObject jObj = new JSONObject(result);
donnees = jObj.getString("message");
Intent ourIntent = new Intent(Subscribe.this,
SubscribeMess.class);
// objet qui vas nous permettre de passe des variables ici la
// variable passInfo
Bundle objetbunble = new Bundle();
objetbunble.putString("message", donnees);
ourIntent.putExtras(objetbunble); // on passe notre objet dans l'intent
// on appelle notre activité
startActivity(ourIntent);
} catch (JSONException e) {
Log.i("tagjsonexp", "" + e.toString());
} catch (ParseException e) {
Log.i("tagjsonpars", "" + e.toString());
}
} else {
Dialog d = new Dialog(Subscribe.this);
d.setTitle(etPwdSub.getEditableText() +" "+etPwdConf.getEditableText());
d.show();
}
} else {
Dialog d = new Dialog(Subscribe.this);
d.setTitle("Fill in all the fields !");
d.show();
}
}
}
});
}
protected void onPause() {
super.onPause();
finish();
}
}
这是 php 脚本:
<?php
if( isset($_POST['login']) && isset($_POST['pwd']) && isset($_POST['name']) && isset($_POST['firstname'])) {
include("connexion_bdd.php");
if(connexionBDD() == 1){
$login = $_POST['login'];
$pwd = $_POST['pwd'];
$name = $_POST['name'];
$firstname = $_POST['firstname'];
$sql = "SELECT colUserID
FROM userTable
WHERE colUserLogin = '".$login."' ";
$req = mysql_query($sql);
$resultat=mysql_num_rows($req);
if($resultat==0){
$temps = time();
$clef = md5($login . $temps);
$req = mysql_query("INSERT INTO userTable(colUserLogin, colUserPwd, colUserName, colUserFirstname, colUserKey, colUserDate)
VALUES( '$login', '$pwd', '$name', '$firstname', '$clef', '$temps')");
if($req){
$destinataire = $login;
$sujet ="Welcome on SnSR";
$from = "From: SpotnShareReminder@live.com \r\n";
$from .= "Content-Type: text/html; charset=us-ascii\r\n";
$message = ' Clic on the link below :<br/>
<a href="http://localhost/spotnshare/validation_mail.php?usrk='.$clef.' ">
Registration confirmation.
</a> ';
ini_set('SMTP','relay.skynet.be');
if(mail($destinataire,$sujet,$message,$from)){
$msg = 'Check your mailbox to activate your account !';
}
else{
$msg = 'Problem sending you the activation mail !';
$req = mysql_query("DELETE FROM userTable WHERE colUserLogin = '".$pseudo."' ");
}
}
else{
$msg = 'Problem inserting you in our database !';
}
}else{
$msg = 'This email has already been used !';
}
mysql_free_result ($req);
}else{
$msg = "Connexion problem with de DB"
print(json_encode(array("message" => $msg)));
}
}else{
$msg = "Couldn't treat your datas"
}
print(json_encode(array("message" => $msg)));
?>
最佳答案
您的请求http://192.168.1.101/spotnshare/subscribe.php失败并返回非 JSON 字符串(可能是 PHP 错误)。您可以使用
打印出该值Log.i("tagconvertstr", "["+result+"]");
在 new JSONObject 调用之前，在解析之前查看您得到的内容。
编辑:如果您使用 Eclipse，您可以设置一个断点并单步执行以查看发生了什么。
关于php - org.json.JSONException : Value <br of type java. lang.String 无法转换为 JSONObject，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/38803567/