php - 查询sql代码，没有呈现应有的数据

Question

我有点困惑。 当我发送 ORDER BY paramater desc 查询时，它应该加载并按该参数的最高编号到较低编号的顺序显示行顺序。

这是我正在运行的代码:

<?php
        $p = 1;
        $loadusers = mysqli_query($con, "SELECT * FROM `users` ORDER BY `gpower` DESC");
        $z = 0;
        while ($me = mysqli_fetch_array($loadusers)) {
            $z++;
            if (($z % 20) == 0) {
                $p += 1;
            }
            if ($me['id'] == $userinfo['id']) {
                break;
            }
        }
        if (isset($_GET['sp'])) {
            $p = intval($_GET['sp']);
        }
        $sl = (($p * 20) - 20);
        $el = $p * 20;
        $loadrank = mysqli_query($con, "SELECT * FROM `users` ORDER BY `gpower` DESC LIMIT $sl,$el");
        if (mysqli_num_rows($loadrank) < 1) {
            $p = 1;
            $sl = (($p * 20) - 20);
            $el = $p * 20;
            $loadrank = mysqli_query($con, "SELECT * FROM `users` ORDER BY `gpower` DESC LIMIT $sl,$el");
        }
        $i = $sl;
        while ($rs = mysqli_fetch_array($loadrank)) {
            $i++;
            ?>
            <tr <?php echo ($rs['id'] == $userinfo['id']) ? "style='background: #7d2222';" : ""?>>
                <td><?php echo $i; ?></td>
                <td><?php echo secure($rs['name']); ?></td>
                <td><?php echo secure($rs['troops']); ?></td>
                <td><?php echo clanName($con, $rs['name']); ?></td>
                <td><?php echo $rs['gpower']; ?></td>
            </tr>
            <?php
        }
    ?>

这就是我得到的:

大家知道为什么会发生这种事吗？

Answer 1

您得到了 ALPHA 降序排列

将 gpower 转换为 int(在 SQL Server 中)

...Order by cast(gpower as int) Desc