PHP MYSQL 显示打开状态

Question

我需要修改此脚本以仅显示打开的记录。字段称为 statusRP

$result = mysql_query("select id, ref, company, title, forename,
                              surname, tel, fax, mob, statusRP, email 
                       from Client");

  if (!$result) {
      die("Query to show fields from table failed");
  }

   $fields_num = mysql_num_fields($result) ;

Answer 1

据我了解，

$result = mysql_query("select id, ref, company, title, forename, surname, tel, fax, mob, statusRP, email from Client WHERE Client.statusRP = 'Open'";) 

还有一件事，使用 mysqli 而不是 mysql(如果 mysql 不是您的要求)。我想这会成功的。