我用 JavaScript 得到了多个数据库下拉列表，我想在下拉菜单中显示结果。但此时此刻，什么也没有表现出来。它显示地区(下拉菜单)，但不显示国家(下拉菜单)
我的核心代码(我想在国家/地区下拉菜单中显示结果):
<html>
<body>
<script type="text/javascript" src="jquery-3.1.1.min.js"></script>
<script type="text/javascript">
function abc(){
var e = document.getElementById("Region_ID");
var val = e.options[e.selectedIndex].value;
$.post("getSecondDropDown.php",{ Region_ID:val}, function( data ) {
$("#Country_ID").html(data);
});
}
</script>
<form action="/NewService.php" id="ServiceForm" method="post">
Name:<input type="text" name="Service_Name"></br>
Region: <select name="Region_ID" id="Region_ID" onchange="abc()" form="ServiceForm">
<?php
include('config.php');
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare("SELECT Region_ID, Region_Name FROM Regions");
$stmt->execute();
$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);
foreach($stmt as $v) {
echo "<option value='" . $v['Region_ID'] ."'>" . $v['Region_Name'] ."</option>";
}
}
catch(PDOException $e) {
echo "Error: " . $e->getMessage();
}
$conn = null;
?>
</select></br>
Country: <select name="Country_ID" form="ServiceForm">
<script>document.write($("#Country_ID"))</script>
</select></br>
<input type="submit">
</form>
</body>
</html>
第二个 php 文件(getSecondDropDownMenu.php):
<?php
$Region_ID =$_POST['Region_ID'];
$option="";
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare("SELECT Country_ID, Country_Name FROM Countries WHERE Region_ID ='$Region_ID'");
$stmt->execute();
$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);
foreach($stmt as $v) {
echo "<option value='" . $v['Country_ID'] ."'>" . $v['Country_Name'] ."</option>";
}
echo $option;
?>
我认为问题就在这里，但并不真正知道:
Country: <select name="Country_ID" form="ServiceForm">
<script>document.write($("#Country_ID"))</script>
</select></br>
最佳答案
在第二个文件 ( getSecondDropDownMenu ) 中，您需要创建一个函数
<?php
function functionName(){
$Region_ID =$_POST['Region_ID'];
$option[] = null;
try {
$conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
$conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
$stmt = $conn->prepare("SELECT Country_ID, Country_Name FROM Countries WHERE Region_ID ='$Region_ID'");
$stmt->execute();
$result = $stmt->setFetchMode(PDO::FETCH_ASSOC);
foreach($stmt as $v) {
array_push($option, "<option value='" . $v['Country_ID'] ."'>" . $v['Country_Name'] ."</option>");
}
return option;
}
?>
然后在另一个文件中第一个文件包含它 include('getSecondDropDownMenu.php');
然后做
$arrayForSecondDropdown[] = functionName();
然后执行 foreach 操作
foreach($arrayForSecondDropdown as $v){
echo $v;
}
关于javascript - 在下拉列表中显示来自另一个文件的数据(php、mysql、javascript)，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/39723979/