public List<User> arrangeUsers(String option) {
String query = "";
if (option.equals("lastNameAsc")) {
query = "SELECT * FROM ? ORDER BY lastName ASC;";
} else if (option.equals("lastNameDesc")) {
query = "SELECT * FROM ? ORDER BY lastName DESC;";
} else if (option.equals("dobAsc")) {
query = "SELECT * FROM ? ORDER BY dateOfBirth ASC;";
} else if (option.equals("dobDesc")) {
query = "SELECT * FROM ? ORDER BY dateOfBirth DESC;";
}
boolean listChoice;
try (Connection conn = DriverManager.getConnection(URL, USERNAME, PASSWORD);
PreparedStatement stmt = conn.prepareStatement(query);) {
if (searchList.size() > 0) {
stmt.setString(1, "search_results");
searchList.clear();
listChoice = true;
} else {
stmt.setString(1, "users");
users.clear();
listChoice = false;
}
ResultSet result = stmt.executeQuery();
while (result.next()) {
User user = new User();
user.setFirstName(result.getString("firstName"));
user.setLastName(result.getString("lastName"));
user.setDob(result.getDate("dateOfBirth"));
user.setPhoneNumber(result.getString("phoneNumber"));
user.setEmail(result.getString("email"));
user.setUserID(result.getInt("id"));
if (listChoice) {
searchList.add(user);
} else {
users.add(user);
}
}
} catch (SQLException sqle) {
System.err.println(sqle);
sqle.printStackTrace();
return null;
}
if (listChoice) {
return searchList;
} else {
return users;
}
}
上述方法返回错误:
com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException
: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near''users' ORDER BY lastName DESC'
at line 1 " error.
该方法应该根据客户端要求的顺序排列用户列表(表)。有什么建议吗?错误消息的原因是什么?如有必要,我准备提供任何其他详细信息。
最佳答案
表名不能用作参数。它必须是硬编码的。您可以执行以下操作:
public List<User> arrangeUsers(String option) {
String query = "SELECT * FROM ";
if (searchList.size() > 0) {
query += "search_results ";
searchList.clear();
listChoice = true;
} else {
query += "users ";
users.clear();
listChoice = false;
}
if (option.equals("lastNameAsc")) {
query += "ORDER BY lastName ASC;";
} else if (option.equals("lastNameDesc")) {
query += "ORDER BY lastName DESC;";
} else if (option.equals("dobAsc")) {
query += "ORDER BY dateOfBirth ASC;";
} else if (option.equals("dobDesc")) {
query += "ORDER BY dateOfBirth DESC;";
}
boolean listChoice;
try (Connection conn = DriverManager.getConnection(URL, USERNAME, PASSWORD);
PreparedStatement stmt = conn.prepareStatement(query);) {
ResultSet result = stmt.executeQuery();
while (result.next()) {
User user = new User();
user.setFirstName(result.getString("firstName"));
user.setLastName(result.getString("lastName"));
user.setDob(result.getDate("dateOfBirth"));
user.setPhoneNumber(result.getString("phoneNumber"));
user.setEmail(result.getString("email"));
user.setUserID(result.getInt("id"));
if (listChoice) {
searchList.add(user);
} else {
users.add(user);
}
}
} catch (SQLException sqle) {
System.err.println(sqle);
sqle.printStackTrace();
return null;
}
if (listChoice) {
return searchList;
} else {
return users;
}
}
希望有帮助。
关于java - 错误: MySQLSyntaxErrorException in a java-based web app,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40019603/