因此,我试图打印出我的程序中处理某些严重程度的医疗状况(高、中和低)的所有医院,这些医院是从我的程序的另一部分传递过来的。
最初,它会找到正确的严重级别,因此它会检查数据库中的另一个表以查找医院并打印它们。然而,它只打印其中一家医院(有两家医院的严重程度很高,我正在测试),而不是另一家。
任何帮助将不胜感激,我觉得我的循环是错误的。
谢谢。
// Create selection query, get relevant hospitals
String select = "SELECT * FROM hospitals WHERE hospitalSeverityHandling = '" + medicalCondition + "'";
// Get results hospitals in the database
ResultSet results = statement.executeQuery(select);
// When hospitals have been found
if (results.next())
{
results.first();
// Get hospitals with relevant severity
//String hospital = results.getString("hospitalName");
//System.out.println(hospital);
// Respond to user, get hospital selection
// TODO Hospital Selection
JOptionPane.showMessageDialog(null, "A list of hospitals have been retrieved for severity level: " + medicalCondition, "Select available hospital", JOptionPane.INFORMATION_MESSAGE);
// Loop hospitals
while(results.next())
{
String hospital = results.getString("hospitalName");
System.out.println(hospital);
}
}
最佳答案
您丢失了一条记录,因为您使用了 results.next() 两次。
相反,您可以按如下方式使用它:
String select = "SELECT * FROM hospitals WHERE
hospitalSeverityHandling = '" + medicalCondition + "'";
// Get results hospitals in the database
ResultSet results = statement.executeQuery(select);
// Loop hospitals
while(results.next())
{
String hospital = results.getString("hospitalName");
System.out.println(hospital);
}
}
关于java - 尝试检索多个 JDBC 结果,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40579514/