我有 3 个表:movie
、actor
和 movie_actor_mapping
。我编写了一个查询,从表电影和每部电影的 Actor 组中选择数据。但之后我添加了另外两个表movie_player_episode_mapping
和player
,我必须修改我的查询来选择和分组可用于电影的季节。例如,如果表 movie_player_episode_mapping
包含 movie_id = 1
的第 1 季和第 2 季,我必须获取字符串 1,2
。
所以,我的表格:
CREATE TABLE `movie` (
`movie_id` int(11) NOT NULL AUTO_INCREMENT,
`title` varchar(50) DEFAULT NULL,
`rating` float(2,1) DEFAULT NULL,
PRIMARY KEY (`movie_id`),
UNIQUE KEY `title` (`title`)
)
CREATE TABLE `actor` (
`actor_id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`name` varchar(40) DEFAULT NULL,
PRIMARY KEY (`actor_id`),
UNIQUE KEY `name` (`name`)
)
CREATE TABLE `movie_actor_mapping` (
`movie_actor_id` int(10) UNSIGNED NOT NULL AUTO_INCREMENT,
`movie_id` int(10) UNSIGNED DEFAULT NULL,
`actor_id` int(10) UNSIGNED DEFAULT NULL,
PRIMARY KEY (`movie_actor_id`),
UNIQUE KEY `movie_actor_id` (`movie_actor_id`)
)
我的查询:
SELECT title, group_concat(a.name separator ', ') as actors
FROM movie m
INNER JOIN movie_actor_mapping ma ON m.movie_id = ma.movie_id
INNER JOIN actor a ON a.actor_id = ma.actor_id
WHERE m.rating IS NOT NULL
GROUP BY m. movie_id
ORDER BY m.rating DESC;
另一个我的两个表:
CREATE TABLE `movie_player_episode_mapping` (
`movie_id` int(11) UNSIGNED,
`season` tinyint(11) UNSIGNED,
`episode` tinyint(11) UNSIGNED,
`player_id` tinyint(11) UNSIGNED,
`path` TEXT
);
CREATE TABLE `player` (
`player_id` int(11) UNSIGNED NOT NULL PRIMARY KEY AUTO_INCREMENT,
`hostname` VARCHAR(30),
`name` VARCHAR(30),
UNIQUE KEY `name` (`name`)
);
我尝试像这样修改我的查询:
SELECT title, group_concat(a.name separator ', ') as actors, group_concat(mpe.season separator ', ') as seasons
FROM movie m, movie_player_episode_mapping mpe
INNER JOIN movie_actor_mapping ma ON m.movie_id = ma.movie_id
INNER JOIN actor a ON a.actor_id = ma.actor_id
WHERE m.rating IS NOT NULL
GROUP BY m. movie_id
ORDER BY m.rating DESC;
但我遇到错误:[42S22][1054]“on Clause”中的未知列“m.movie_id”
。
我也尝试了下一个查询,但结果错误。例如,如果我的 movie_player_episode_mapping
仅包含 1 个季节的 movie_id=1
行,则我得到 seasons: "1, 1, 1, 1, 1, 1, 1, 1, 1"
而不是 季节:“1”
SELECT title, group_concat(a.name separator ', ') as actors, group_concat(mpe.season separator ', ') as seasons
FROM movie m
INNER JOIN movie_player_episode_mapping mpe ON m.movie_id = mpe.movie_id
INNER JOIN movie_actor_mapping ma ON m.movie_id = ma.movie_id
INNER JOIN actor a ON a.actor_id = ma.actor_id
WHERE m.rating IS NOT NULL
GROUP BY m. movie_id
ORDER BY m.rating DESC;
我的错误在哪里以及如何解决?
最佳答案
SELECT title, group_concat(a.name separator ', ') as actors, group_concat(mpe.season separator ', ') as seasons
FROM movie m
INNER JOIN movie_actor_mapping ma ON m.movie_id = ma.movie_id
INNER JOIN actor a ON a.actor_id = ma.actor_id, movie_player_episode_mapping, mpe
WHERE m.rating IS NOT NULL
GROUP BY m. movie_id
ORDER BY m.rating DESC;
也许这可以帮助您...您上次的查询
关于mysql - 从两个 MySQL 表中选择时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41074014/