php - 回显 SELECT COUNT(*) 查询的结果

Question

在我的网站上，我在许多不同的设置中展示不同的产品，因此为了确保结果数量正确，我想用 PHP 来回显它们。到目前为止，我已经尝试按照我所知道的方式回应他们，但没有成功。

我想要回显的页面上的代码包含对顶部函数文件的要求。我尝试过:

<?php
//Call the count_stock() function
$result_count = count_stock();
?>
<p>Showing 1-9 of <?php echo $result_count['COUNT(*)']; ?> results.</p>
<p>Showing 1-9 of <?php echo $result_count[0]; ?> results.</p>
<p>Showing 1-9 of <?php print_r($result_count[0]); ?> results.</p>

我执行查询的函数是:

//create a function to count get_stock
function count_stock() {
    global $conn;
    //query the database to count the data entries in the stock table
    $sql = 'SELECT COUNT(*) FROM stock';
    //use a prepared statement to enhance security
    $statement = $conn->prepare($sql);
    $statement->execute();
    $result_count = $statement->fetchAll();
    $statement->closeCursor();
    return $result_count;
}

Answer 1

将您的功能更改为:

function count_stock() {
        global $conn;
        //query the database to count the data entries in the stock table
        $sql = 'SELECT COUNT(*) as tot FROM stock';
        //use a prepared statement to enhance security
        $statement = $conn->prepare($sql);
        $statement->execute();
        $result_count = $statement->fetch();
        $statement->closeCursor();
        return $result_count['tot'];
    }