表格
mysql> SELECT * FROM swaps_products;
+----+---------+-----------+------------+-----------+---------------------+
| id | swap_id | holder_id | swap_to_id | product_id| added |
+----+---------+-----------+------------+-----------+---------------------+
| 1 | 9 | 3 | 0 | 32 | 2017-01-06 10:43:52 |
| 2 | 11 | 13 | 0 | 3 | 2017-01-06 11:03:45 |
| 3 | 11 | 13 | 0 | 4 | 2017-01-06 11:03:45 |
| 4 | 11 | 3 | 0 | 32 | 2017-01-06 11:03:45 |
| 5 | 11 | 3 | 0 | 31 | 2017-01-06 11:03:45 |
| 6 | 11 | 3 | 0 | 30 | 2017-01-06 11:03:45 |
| 7 | 12 | 3 | 0 | 32 | 2017-01-06 14:16:13 |
| 8 | 12 | 3 | 0 | 31 | 2017-01-06 14:16:13 |
| 9 | 12 | 2 | 0 | 2 | 2017-01-06 14:16:13 |
| 10 | 12 | 2 | 0 | 1 | 2017-01-06 14:16:13 |
| 11 | 13 | 13 | 3 | 3 | 2017-01-12 14:31:44 |
| 12 | 13 | 13 | 3 | 4 | 2017-01-12 14:31:44 |
| 13 | 13 | 3 | 13 | 32 | 2017-01-12 14:31:44 |
| 14 | 13 | 3 | 13 | 31 | 2017-01-12 14:31:44 |
对于swap_id = 13
,涉及四种产品 - 3、4、31、32。我需要查询,该查询将为我提供所有其他涉及 3,4,31,32 个产品中的任何交换(swap_id 列表)。
我有这个
SELECT sp.swap_id as swap_id, sp.holder_id as holder_id
-> FROM swaps_products as sp
-> JOIN swaps as s
-> ON s.id=sp.swap_id
-> WHERE (sp.swap_id != 13) AND
-> (s.rejected IS NULL) AND
-> ((s.swapped IS NULL) OR (s.swapped2 IS NULL)) AND
-> (sp.product_id IN (3,4,31,32));
JOIN 对于问题来说并不重要。这个查询有效,但问题是我只知道 swap_id。所以我尝试了这个:
(sp.product_id IN (SELECT product_id FROM swaps_products WHERE swap_id = 13));
但出现错误:
ERROR 1064 (42000): You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'JOIN swaps as s
ON s.id=sp.swap_id
WHERE (sp.swap_id != 13) AND
(s.rejected IS N' at line 2
我认为问题是子查询没有返回 IN 语句所期望的数组。
最佳答案
IN 语句要求结果是要检查的单列值向量。
直接回答您的询问:
从 swaps_products 中选择*,其中product_id位于
(从 swaps_products 中选择 Product_id,其中 swap_id = 13)
并且 swap_id != 13
此外,根据上面的错误消息,您遇到的语法错误指向第2行;我怀疑您在 where...in
查询中遗漏了 FROM swaps_products as sp
部分。
关于mysql - 如何将 MySQL WHERE IN 语句与子查询一起使用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41617633/