javascript - 在 jquery ui 自动完成中允许 null

Question

我目前收到此错误。

未捕获类型错误:无法读取 null 的属性“标签”

return $.extend( {}, item, {
            label: item.label || item.value,
            value: item.value || item.label
        } );

这行代码是在 jquery-ui 中给我错误的代码。

我知道导致错误的是空值。 我怎样才能允许它，或者如果不允许的话，如何阻止空值作为结果之一返回？

这是 mysql 查询:

 $get_company = "SELECT DISTINCT companies.company,companies.company_id
        FROM companies
        INNER JOIN target_details
        ON companies.company_id = target_details.company_id
        WHERE companies.company LIKE \"%$company%\"
        LIMIT 1500 OFFSET 10
        ";
        if($run_company = $conn->query($get_company)){
            while($row = $run_company->fetch_assoc()){
                $data[] = $row['company'].$row['company_id'];
            }

echo json_encode($data);        

Answer 1

我认为最好将查询中的空值“转换”为空字符串，例如:

更新:您还需要更改循环。

$get_company = "SELECT DISTINCT NVL(companies.company, ''), NVL(companies.company_id, 0)
        FROM companies
        INNER JOIN target_details
        ON companies.company_id = target_details.company_id
        WHERE companies.company LIKE \"%$company%\"
        LIMIT 1500 OFFSET 10
        ";
        if($run_company = $conn->query($get_company)){
            while($row = $run_company->fetch_assoc()){
                $data_row["label"] = $row['company'].$row['company'];
                $data_row["value"] = $row['company'].$row['company_id'];
                array_push($data, $data_row);
            }

echo json_encode($data);