php - 如何在 Laravel 5 中返回自定义查询结果

Question

用户表

+------------+
|    User    |
+------------+
| uid        |
| name       |
| created_at |
| updated_at |
+------------+

汽车表

+------------+
|    Car     |
+------------+
| cid        |
| uid        |
| car_name   |
| created_at |
| updated_at |
+------------+

我正在使用查询生成器和我的查询:

DB::table('user')
   ->join('car', 'user.uid', '=', 'car.uid')
   ->where('user.uid', '=', $uid)
   ->get();

它从汽车表中截断了created_at和updated_at，它让我明白了:

{
  "uid": 5,
  "name": "Alexander Lowe DVM",
  "created_at": "2017-04-01 18:12:45",
  "updated_at": "2017-04-01 18:12:45",
  "cid": 5,
  "car_name": "BMW X8",
}

我想让我们的查询结果变成，我该怎么做？有什么解决办法吗？

{
  "uid": 5,
  "name": "Alexander Lowe DVM",
  "created_at": "2017-04-01 18:12:45",
  "updated_at": "2017-04-01 18:12:45",
  "car": {
    "cid": 5,
    "car_name": "BMW X8",
    "created_at": "2017-04-01 18:12:45",
    "updated_at": "2017-04-01 18:12:45"
  }
}

.

Answer 1

试试这个，看看你会得到什么:

$users = DB::table('user')
            ->join('car', 'user.uid', '=', 'car.uid')
            ->where('user.uid', '=', $uid)
            ->select('user.*', 'car.created_at', 'car.updated_at')
            ->get();