MySQL子查询仍然产生双SUM值

Question

我确信我做错了什么，因为我已经遵循了找到的所有示例。 我确实得到了结果，但总数加倍或大量重复。

查询是:

select 

(st.total_cells) as 'Cells Sorted',

from abstract_freeze af
left join abstract_ejaculate_collection aec on af.ejaculate_collection_id = aec.id
left join mo_flo on aec.id = mo_flo.ejaculate_collection_id
left join sample_time st on mo_flo.id = st.mo_flo_id
left join collection_schedule cs on aec.collection_schedule_id = cs.id
left join collection_plan cp on cs.collection_plan_id = cp.id
left join sub_admission sa on cp.sub_admission_id = sa.id
left join master_admission ma on sa.master_admission_id = ma.id
left join animal on ma.animal_id = animal.id
where aec.tenant_id = 8 and date(aec.scheduled) = '2017-04-12' and sa.type = 'Sexed'
group by aec.id;

将有多个具有相同ejaculate_collection_id的abstract_freeze记录，因此我的SUM(st.total_cells)重复项基于重复的af.ejaculate_collection_id的数量。

我似乎无法让我的查询或子查询正确，我需要基于分组的total_cells 总和。

Answer 1

如果每个 id 有多个记录，那么您可能需要每个 id SUM 而不仅仅是总数，您可以尝试以下操作:

select aec.id, SUM(st.total_cells) as 'Cells Sorted',
from abstract_freeze af
left join abstract_ejaculate_collection aec on af.ejaculate_collection_id = aec.id
left join mo_flo on aec.id = mo_flo.ejaculate_collection_id
left join sample_time st on mo_flo.id = st.mo_flo_id
left join collection_schedule cs on aec.collection_schedule_id = cs.id
left join collection_plan cp on cs.collection_plan_id = cp.id
left join sub_admission sa on cp.sub_admission_id = sa.id
left join master_admission ma on sa.master_admission_id = ma.id
left join animal on ma.animal_id = animal.id
where aec.tenant_id = 8 and date(aec.scheduled) = '2017-04-12' and sa.type = 'Sexed'
group by aec.id;