mysql - ＃1064-SQL语法错误，如何解决？

Question

当我创建一个TRIGGER时，我的数据库中有3个表[table_a，table_b，dataz]，

CREATE TRIGGER trigz AFTER INSERT ON table_a
FOR EACH ROW
    IF EXISTS (SELECT * FROM table_b WHERE table_b.uid = '123') THEN
        INSERT INTO dataz
            VALUES('123');

以ERROR为

 #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 5

我不明白我在这里想念的是什么...

我正在使用WAMP Server 2.4，有人有解决方案吗？



编辑1（对于Nigel Ren）::

SQL：

CREATE TRIGGER trigz AFTER INSERT ON table_a FOR EACH ROW 
IF EXISTS (SELECT * FROM table_b WHERE table_b.uid = 1) THEN
    BEGIN
        INSERT INTO dataz(userid) VALUES('123');
    END;
END IF; 

错误：

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 4 

Answer 1

这取决于编辑器识别语句结束的方式。通常它使用;，但是随着过程在各处使用;，您需要对其进行更改。所以像

DELIMITER $$

CREATE TRIGGER trigz AFTER INSERT ON Bin FOR EACH ROW 
begin
IF EXISTS (SELECT * FROM Bin WHERE binID = 1) THEN
        INSERT INTO log(text) VALUES('123');
END IF; 
end;
$$

编辑：
应该使用：

DELIMITER;

最后将定界符重置为正常。