php - 将查询插入在线 MySQL 数据库不起作用

Question

我正在尝试将数据插入在线 MySql 数据库中，几个月前我使用过此查询，现在它似乎不起作用，

我的表格:

$name = "Hilary";
$number = "768";
$orderss = "Rice x1";
$location = "Chilenje";

$con= mysqli_connect($host,$user,$pass,$db);

$query= "insert into orders values('".$name."','".$number."','".$orderss."','".$location."');";

$result= mysqli_query($con,$query);

if(!$result)
{
    $response = array();
    $code= "reg_false";
    $message="Error Placing Order...";
    array_push($response,array("code"=>$code,"message"=>$message));
    echo json_encode(array("server_response"=>$response));

}
else
{
    $response = array();
    $code= "reg_true";
    $message="Order Successful,Please wait for our call...";
    array_push($response,array("code"=>$code,"message"=>$message));
    echo json_encode(array("server_response"=>$response));

}

mysqli_close($con);

?>

当我运行此表单时，我收到服务器响应的“下订单时出错”部分，并且未插入值。请帮助我

Answer 1

如果您要插入表的所有列，请使您的 $query 非常简单

$stmt = $conn->prepare("INSERT INTO orders VALUES (?, ?, ?, ?)");
$stmt->bind_param("siss", $name, $number, $orderss, $location);

或者，如果您要插入特定列，则可以通过将 column_name* 替换为您的实际列名称来使用它

$stmt = $conn->prepare("INSERT INTO orders (column_name1, column_name2, column_name3, column_name4) VALUES (?, ?, ?, ?)");
$stmt->bind_param("siss", $name, $number, $orderss, $location);

或者我还修改了您当前的代码，以便您可以在最后测试一件事“siss”是4种不同类型的参数i - 整数，d - double ，s - 字符串，b - BLOB

<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";

$name = "Hilary";
$number = "768";
$orderss = "Rice x1";
$location = "Chilenje";

// Create connection
$con = new mysqli($servername, $username, $password, $dbname);

// Check connection
if ($con->connect_error) {
    die("Connection failed: " . $con->connect_error);
}

// prepare and bind
$stmt = $conn->prepare("INSERT INTO orders VALUES (?, ?, ?, ?)");
$stmt->bind_param("siss", $name, $number, $orderss, $location);

if($stmt->execute()) {
$stmt->execute();
    $response = array();
    $code= "reg_true";
    $message="Order Successful,Please wait for our call...";
    array_push($response,array("code"=>$code,"message"=>$message));
    echo json_encode(array("server_response"=>$response));
} else {

    $response = array();
    $code= "reg_false";
    $message="Error Placing Order...";
    array_push($response,array("code"=>$code,"message"=>$message));
    echo json_encode(array("server_response"=>$response));

}
$stmt->close();
$con->close();
?>