php - MySql关系型数据库困惑

Question

我一直在尝试使用 PHP 显示 MySql NOTES 表中与 QUOTES 表中的特定 NAME 匹配的所有结果。目标是我想显示每个特定名称下列出的所有评论。

QUOTES 表列:ID/NAME/EMAIL/PRICE

NOTES 表列:ID/NAME/AGENT/DATE/COMMENTS

这是我正在使用的 MySql 代码:

mysql_select_db($database_dbConnect, $dbConnect);
$query_rsquotes = "SELECT * FROM quotes ORDER BY `id` DESC";
$rsquotes = mysql_query($query_rsquotes, $dbConnect) or die(mysql_error());
$row_rsquotes = mysql_fetch_assoc($rsquotes);
$totalRows_rsquotes = mysql_num_rows($rsquotes);

mysql_select_db($database_dbConnect, $dbConnect);
$query_rsnotes = "SELECT quotes.*, notes.* FROM quotes INNER JOIN notes ON quotes.name = notes.name ORDER BY notes.date DESC";
$rsnotes = mysql_query($query_rsnotes, $dbConnect) or die(mysql_error());
$row_rsnotes = mysql_fetch_assoc($rsnotes);
$totalRows_rsnotes = mysql_num_rows($rsnotes);

然后显示结果:

<?php do { ?>
    <?php echo $row_rsquotes['name']; ?>
    <?php echo $row_rsquotes['email']; ?>

<?php
    if ($row_rsquotes['name'] == $row_rsnotes['name']) {
        do {
            if ($row_rsquotes['name'] == $row_rsnotes['name']) {
                echo "<div class='agentNotes'><p><strong>DATE: </strong><span class='meta-date'>" . $row_rsnotes['date'] . "</span></p><p><strong>AGENT:</strong> " . $row_rsnotes['agent'] . "</p><p><strong>AGENT NOTES:</strong> " . $row_rsnotes['comments'] . "</p></div>";
             }
        } while ($row_rsnotes = mysql_fetch_assoc($rsnotes));
    }
?>

<?php } while ($row_rsquotes = mysql_fetch_assoc($rsquotes)); ?>

它循环并显示该特定名称的匹配记录，但当它到达下一个名称时，它不会显示匹配的注释。我做错了什么？

Answer 1

query names_table containing Names
foreach(Names as Name){
    Query comment_table for comments that relates or maps Name
    foreach(comments as comment){
        display comment
     }
}